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IceJOKER [234]
3 years ago
13

A 4-way set associative cache has 64 blocks of 16 words. How many bits are there in the ""tag"" field of the 15-bit address for

this architecture
Computers and Technology
1 answer:
Tanya [424]3 years ago
6 0

Answer:

3 bits

Explanation:

Given a 4- way set associative cache that has 64 blocks of 16 words.

Therefore, the number of sets cache has:

\frac{64}{4} = 16

Now,

Cache data size is 16kB

The number of cache blocks can be calculated as:

16kB/16 = 1024 bytes/16 byte\times 16 = 256 cache blocks

Now,

Total sets = \frac{cache blocks}{associative sets}

Total sets = \frac{256}{4} = 64

Now,

2^{n} = 64

n = 6

For 15 bit address for the architecture, the bits in tag field is given by:

15 - (6 + 6) = 3 bits

Thus the tag field will have 3 bits

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Answer:

Following are the program in the C++ Programming Language.

//set header file

#include <iostream>

//set namespace

using namespace std;

//define class

class format

{

//set access modifier

public:

//set string type variable

 string res;

//define function

 void names(string first_name, string last_name)

 {  

//set if-else if condition to check following conditions

   if(first_name.length()>0 && last_name.length()>0)

   {

     res="Name: "+last_name+", "+first_name;

   }

   else if(first_name.length()>0 and last_name.length()==0)

   {

     res="Name: "+first_name;

   }

   else if(first_name.length()==0 and last_name.length()==0)

   {

     res="";

   }

 }

//define function to print result

 void out(){

   cout<<res<<endl;

 }

};

//define main method

int main() {

//set objects of the class

 format ob,ob1,ob2;

//call functions through 1st object

 ob.names("John","Morris");

 ob.out();

//call functions through 2nd object

 ob1.names("Jhon","");

 ob1.out();

//call functions through 3rd object

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 ob2.out();

}

<u>Output</u>:

Name: Morris, John

Name: Jhon

Explanation:

<u>Following are the description of the program</u>:

  • Define class "format" and inside the class we define two void data type function.
  1. Define void data type function "names()" and pass two string data type arguments in its parameter "first_name" and "last_name" then, set the if-else conditional statement to check that if the variable 'first_name' is greater than 0 and 'last_name' is also greater than 0 then, the string "Name" and the following variables added to the variable "res". Then, set else if to check that if the variable 'first_name' is greater than 0 and 'last_name' is equal to 0 then, the string "Name" and the following variable "first_name" added to the variable "res".
  2. Define void data type function "out()" to print the results of the variable "res".
  • Finally, we define main method to pass values and call that functions.
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