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neonofarm [45]
4 years ago
15

Need help I am horrible at math

Mathematics
2 answers:
Serga [27]4 years ago
8 0

B) x = 1

Coordinates (1,3) and (1,1) both fall on the x-axis of 1. Since the slope is undefined, the y-intercept would be used in the slope-intercept form y = mx + b. (:

IRINA_888 [86]4 years ago
6 0
X=1 because the line is undefined and both points have an x coordinate through 1
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Generally plug 0 in for x and solve for y. whatever y is is your y intercept
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3 years ago
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Consider the circle of radius 5 centered at (0,0), how do you find an equation of the line tangent to the circle at the point (3
Flauer [41]

\text{We know that the tangent at any point on a circle is perpendicular}\\
\text{to the radius at that point.}\\
\\
\text{so first we find the equation of the line joining (0,0) and (3,4)}\\
\text{and then using the slope, we find the line perperndicular to it at (3,4)}\\
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\text{the equation of the line passing through (0,0) and (3,4) is}\\
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y-0=\frac{4-0}{3-0}(x-0)

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\text{so the slope of radius is }m=\frac{4}{3}.\\
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\text{we know that the product of the perpendicular lines is }-1. \\
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\text{so the slope of the perpendicular line would be}=-\frac{1}{4/3}=-\frac{3}{4}\\
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\text{So the equation of the tangent line has slope }-\frac{3}{4} \text{ and}\\
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y-4=-\frac{3}{4}(x-3)\\
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\Rightarrow y-4=-\frac{3}{4}x+\frac{9}{4}\\
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\Rightarrow y=-\frac{3}{4}x+\frac{9}{4}+4\\
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\text{so the equation of tangent line is:} y=-\frac{3}{4}x+\frac{25}{4}

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Answer:

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4 0
3 years ago
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Answer:1/7

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Answer:

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