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3 years ago

What is the value of x? Enter your answer in the box. x =

Mathematics

2 answers:

shepuryov [24]3 years ago

4 0

I think the value of x may be 1. I’m not entirely sure, though.

tekilochka [14]3 years ago

4 0

Answer:

$x=19$

Step-by-step explanation:

We have been given a diagram of two intersecting lines. We are asked to find the value of x.

We know that measure of two vertical angles is always equal.

We can see that angle $3x-3$ and $6(x-10)$ are vertical angles, so we will equate measure of both angles and solve for x as:

$6(x-10)=3x-3$

$6\cdot x-6\cdot 10=3x-3$

$6x-60=3x-3$

$6x-60+60=3x-3+60$

$6x=3x+57$

$6x-3x=3x-3x+57$

$3x=57$

$\frac{3x}{3}=\frac{57}{3}$

$x=19$

Therefore, the value of x is 19.

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What is the equation of the line with a slope of 4/3 and y-intercept of -6

skelet666 [1.2K]

Answer:

y=4/3x-6

Step-by-step explanation:

y=mx+b

m= 4/3

b= -6

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4 years ago

HELP ME WITH THIS! <br> Plz

Lelu [443]

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3 years ago

Find f(-3) if f(x) = x 2.

vlabodo [156]

Answer:

f(-3) = 9

Step-by-step explanation:

Lets define f(a) first where a is any integer,

f(a) is found out by putting the integer in the function in place of the variable

So for the given question

$f(x) = x^{2}$

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So putting -3,

$f(-3) = (-3)^{2}$

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So, the value of function at -3 is 9 ..

5 0

4 years ago

Read 2 more answers

find the three consecutive odd integers such that the sum of twice the first and three times the second is 67 more than twice th

Elenna [48]

Answer:

23, 25, 27

Step-by-step explanation:

It can be convenient to work "consecutive integer" problems by using a variable to represent the middle one.

<h3>setup</h3>

Let x represent the middle integer. Then (x-2) is the first of the three odd integers, and (x+2) is the third. The given relation is ...

2(x -2) +3x = 67 +2(x +2)

<h3>solution</h3>

5x -4 = 2x +71 . . . . . simplify

3x = 75 . . . . . . . . add 4-2x

x = 25 . . . . . . . divide by 3

The three integers are 23, 25, 27.

4 0

2 years ago

f(x) = square root ( x^4 -16x^2) let f be the function given by: . . a) Find the domain of f.. b) Find f '(x). c) Find the slope

Bond [772]

A ) The domain:
$x^{4} -16 x^{2} \geq 0 \\ x^{2} ( x^{2} -16) \geq 0 \\ x^{2} -16 \geq 0 \\ x^{2} \geq 16$
x ≤ -4 and x≥ 4 or: x ∈ ( - ∞ , - 4 ) ∪ ( 4 , + ∞ )
b ) f ` ( x ) = $\frac{1}{2 \sqrt{ x^{4} -16 x^{2} } } *( 4 x^{3} - 32 x ) = \\ = \frac{2x( x^{2} -8)}{ \sqrt{ x^{4}-16 x^{2} } }$
c ) The slope of the line normal to the graph at x = 5
m = -1 / f `(x)
f ` ( x ) = $\frac{10(25-8)}{ \sqrt{625-400} }= \frac{10*17}{15} = \frac{34}{3}$
m = - 3/34

8 0

3 years ago