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nikitadnepr [17]
3 years ago
8

Evaluate 8+3e when e= 2.

Mathematics
2 answers:
Norma-Jean [14]3 years ago
6 0

Answer:

14.

Step-by-step explanation:

8+3e = 8 + 3·2,

8+3e = 8 + 6,

8+3e = 14.

14 = 14

Therefore, your answer is 14!

Hope this helps.

trapecia [35]3 years ago
5 0

\text{Hey there!}

\text{If e = 2 then replace the e in the equation to 2}

\mathsf{8+3e}\\\mathsf{= 8+3(2)}\\\mathsf{3(2)=6}\\\mathsf{8+6=14}\\\\\boxed{\boxed{\mathsf{Answer: \boxed{\mathsf{14}}}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\dfrac{\frak{LoveYourselfFirst}}{:)}

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Answer:

Go to desmos and it will answer literally all of your graphing questions. Just type in desmos graphing calculator.

Step-by-step explanation:

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3 years ago
A straight angle has four angles. angle 1=39º, angle 2=54º, angle 3=48º, what is the measure of angle 4 ?
Ludmilka [50]

Answer:

39 degrees

Step-by-step explanation:

Add: 39+54+48=141

180 (degrees of a straight angle) minus 141=39

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Hope I helped!! :)

Brainliest?!?!

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8 0
2 years ago
(12x5+3x25)-8<br><br> 12x5=60<br> 3x25=75<br> 60+75=135<br> 135-8=127
lions [1.4K]

Answer:

127

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
5/7 x 21/25 what is the answer to this???!!?!?!!!?
lbvjy [14]
Multiply the tops and multiply the bottoms
Aka
5*21
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7*25

And simplify
5 0
3 years ago
Solve the system of linear equations for x and y.(cos θ)x + (sin θ)y=1(−sin θ)x + (cos θ)y = 0x=y=
lys-0071 [83]

Answer:

\bold{x =cos\theta}\\\bold{y=sin\theta}

Step-by-step explanation:

The given system of linear equations is:

(cos\theta)x+(sin\theta)y=1\\(-sin\theta)x+(cos\theta)y=0

We have to solve the equations for the values of x, y.

Let us use elimination method in which we eliminate one of the variables from the two variables.

For this, let us multiply the first equation by sin\theta and second equation by cos\theta

Now, the equations become:

(cos\theta.sin\theta)x+(sin\theta.sin\theta)y=sin\theta\\\Rightarrow (cos\theta.sin\theta)x+(sin^2\theta)y=sin\theta ....... (1)\\\\(-sin\theta.cos\theta)x+(cos\theta.cos\theta)y=0\\\Rightarrow (-sin\theta.cos\theta)x+(cos^2\theta)y=0 ..... (2)

Now, let us add (1) and (2):

(sin^2\theta)y+(cos^2\theta)y=sin\theta\\\Rightarrow (sin^2\theta+cos^2\theta)y=sin\theta\\\Rightarrow (1)y=sin\theta\\\Rightarrow y = sin\theta

Using the equation:

(-sin\theta)x+(cos\theta)y=0

Putting value of y:

\Rightarrow (-sin\theta)x+(cos\theta)sin\theta=0\\\Rightarrow (sin\theta)x=(cos\theta)sin\theta\\\Rightarrow x = cos\theta

So, the answer to the system of linear equations is:

\bold{x =cos\theta}\\\bold{y=sin\theta}

7 0
3 years ago
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