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Elden [556K]
3 years ago
10

Use the sample data and confidence level to construct the confidence interval estimate of the population proportion p. n=500, x=

200, 95% confidence
Mathematics
1 answer:
DiKsa [7]3 years ago
5 0

Answer:

0.3581<x<0.4429

Step-by-step explanation:

Using the formula for calculating the confidence interval of the population proportion p expressed as:

Confidence interval = p ± Z * √p(1-p)/n

p is the population proportion = x/n

p = 200/500

p = 0.4

Z is the z-score at 95% CI = 1.96

n is the sample size = 500

Substituting the given parameters into the formula we will have;

Confidence interval = 0.4 ± 1.96 * √p(1-p)/n

Confidence interval = 0.4 ± 1.96 * √0.4(0.6)/500

Confidence interval = 0.4 ± 1.96 * √0.24/500

Confidence interval = 0.4 ± 1.96 * √0.00048

Confidence interval = 0.4 ± 1.96 * 0.0219

Confidence interval = 0.4±0.04294

Confidence interval = (0.3571, 0.4429)

Hence the confidence interval of the population mean is 0.3581<x<0.4429

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Answer:

- 4.67

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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We know it passes through the point (-3,7), substituting x and y, we would then get our new equation, (7) = \frac{1}{3}( -3) + b.

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3 0
3 years ago
The sum of two numbers is 110.The larger number is 2 less than 7 times the smaller.Find the Large number
natima [27]

Answer:

The larger number is 96.

Step-by-step explanation:

let \: the \: two \: numbers \: be \: a \: and \: b \\ a + b = 110 \\ let \: a \: be \: the \: larger \: number \\ a = 7b - 2 \\ we \: can \: get \: the \: value \: of \: b \: by \: substituting \: the \: value \: above \: for \: a \: in \: eq \: 1 \\ 7b - 2 + b = 110 \\ 8b - 2 = 110 \\ 8b = 110 + 2 \\ 8b = 112 \\ b = \frac{112}{8}  \\b = 14\\ calculate \:the \: value \: of \: a \: using \: the \: equation \: above \\ a + b = 110 \\ a = 110 - 14 \\ a = 96 \\ hence \: the \: large \: number \: is \: 96

8 0
2 years ago
How do you put 5.96 as a fraction
Genrish500 [490]
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Step-by-step explanation:

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