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SOVA2 [1]
3 years ago
5

Multiply. Write your answer in lowest terms as a proper or improper fraction. 3/4 (-2/15)

Mathematics
1 answer:
alexira [117]3 years ago
7 0
Top*top and bottom*bottom
(3*-2)/(4*15)=-6/60=-1/10
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Xsquare + 10x + 16 equals 0
inn [45]
X^2+10x+16=0

First, you find factors of 16.
1 x 16
2 x 8
4 x 4

Next, you find which of the factor pairs adds up to 10 (from the 10x). In this case, 2 x 8 because 2 times 8 is 16 and 2 plus 8 is 10.

Then, the equation will be written out as: (x+2) (x+8). Take those two equations and set them equal to 0, and then solve.

x+2=0
-2 -2
x=-2

x+8=0
-8 -8
x=-8

So, your answers are x=-2 and x=-8. You can check by plugging in those two numbers as x.

7 0
3 years ago
A tank that is 30% full contains 651 gallons of water. How much water does the tank hold when it is full?
Andreas93 [3]

last one 2170

Answer:

651=30 percent

x=100 percent

x=( 100×651)/30=2170 gallons

3 0
3 years ago
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Please help! picture attached :)
Radda [10]

Answer:

y=-3x+4

Step-by-step explanation:

im assuming that you need the equation of the table

to find slope, y2-y1/x2-x1    10-4/-2-0

6/-2=-3   slope=-3  

y=mx+b   just sub in the numbers from a point in the table

10=-3(-2)+b

10=6+b

b=4

y=-3x+b

4 0
2 years ago
The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili
Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean of a population is 74 and the standard deviation is 15.

This means that \mu = 74, \sigma = 15

Question a:

Sample of 36 means that n = 36, s = \frac{15}{\sqrt{36}} = 2.5

This probability is 1 subtracted by the pvalue of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{78 - 74}{2.5}

Z = 1.6

Z = 1.6 has a pvalue of 0.9452

1 - 0.9452 = 0.0548

0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

Question b:

Sample of 150 means that n = 150, s = \frac{15}{\sqrt{150}} = 1.2247

This probability is the pvalue of Z when X = 77 subtracted by the pvalue of Z when X = 71. So

X = 77

Z = \frac{X - \mu}{s}

Z = \frac{77 - 74}{1.2274}

Z = 2.45

Z = 2.45 has a pvalue of 0.9929

X = 71

Z = \frac{X - \mu}{s}

Z = \frac{71 - 74}{1.2274}

Z = -2.45

Z = -2.45 has a pvalue of 0.0071

0.9929 - 0.0071 = 0.9858

0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c. A random sample of size 219 yielding a sample mean of less than 74.2

Sample size of 219 means that n = 219, s = \frac{15}{\sqrt{219}} = 1.0136

This probability is the pvalue of Z when X = 74.2. So

Z = \frac{X - \mu}{s}

Z = \frac{74.2 - 74}{1.0136}

Z = 0.2

Z = 0.2 has a pvalue of 0.5793

0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

5 0
3 years ago
Do you know why your friend is wrong
arsen [322]

Answer:

i think so what is aap name

7 0
3 years ago
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