Question

A vendor sells h hot dogs and s sodas. If a hot dog costs twice as much as a soda, and if the vendor takes in a total of d dollars, how many cents does a soda cost?
AND NOT THE STUPID FORMULA 100d(2h+s) or p= d/2h+s


OK???????

Answer 1

Answer:D/3

Explanation:

Answer 2

Answer:

The cost of a soda is $\dfrac{100d}{(2h+s)}$  cents.

Explanation:

It is given that a hot dog costs twice as much as a soda.

Let x be the cost of a soda in cents.

Cost of a hot dog = 2x cents.

It is given that a vendor sells h hot dogs and s sodas. So, the total cost s

$Cost=2x(h)+x(s)$

The vendor takes in a total of d dollars.

1 dollar = 100 cents

d dollars = 100d cents.

It means total cost is 100d.

$2x(h)+x(s)=100d$

$x(2h+s)=100d$

Divide both sides by (2h+s).

$x=\dfrac{100d}{2h+s}$

Therefore,  cost of a soda is $\dfrac{100d}{(2h+s)}$  cents.