All categories

2 years ago

300 L= mL I NEED THE ANSWER RIGHT NOW

Mathematics

2 answers:

vodka [1.7K]2 years ago

5 0

Explanation + Answer: First, 1 Liter equals 1,000 Milliliters.

If you need 300 liters to Milliliters, we need to do multiplication.

You need to think, 300 x 1000= ?

Well 3 x 1 = 3 and add 5 zeroes, 300000 mL.

Hope this helps.

sergiy2304 [10]2 years ago

4 0

Answer:

300000ml

Step-by-step explanation:

Litres to ml = * 1000

300L * 1000 = 300000ml

You might be interested in

Rewrite each expression using the distributive property. 1. (a X 4) + (a x 3) =

Darina [25.2K]

Answer:

(a x 4)+(a x 3)=7a

Step-by-step explanation:

(a x 4)+(a x 3)= 4a+3a

(a x 4)+(a x 3)=7a

or does your question means something else??

3 0

3 years ago

Ebony earned scores of 72 70, 81, 99, and 88 on five math tests. Determine her

Minchanka [31]

Let it be x

$\boxed{\sf Average=\dfrac{Sum\:of\:terms}{No\:of\:terms}}$

$\\ \sf\longmapsto \dfrac{72+70+81+99+88+x}{6}=83$

$\\ \sf\longmapsto \dfrac{410+x}{6}=83$

$\\ \sf\longmapsto 410+x=498$

$\\ \sf\longmapsto x=498-410$

$\\ \sf\longmapsto x=88$

6 0

3 years ago

A toy manufacturer wants to know how many new toys children buy each year. A sample of 601 children was taken to study their pur

Lilit [14]

Answer:

The confidence interval is 6.6<μ<6.8.

Step-by-step explanation:

We have:

Number of observations = 601

Mean = 6.7

Standard deviation σ = 1.5

The z-score for a 95% confidence interval is 1.96.

The limits of the confidence interval can be calculated as

$X \pm z*\frac{\sigma}{\sqrt{n}}\\\\LL=X-z*\frac{\sigma}{\sqrt{n}}=6.7-1.96*\frac{1.5}{\sqrt{601} } =6.7-0.1199=6.6\\\\UL=X+z*\frac{\sigma}{\sqrt{n}}=6.7+1.96*\frac{1.5}{\sqrt{601} } =6.7+0.1199=6.8$

The confidence interval is 6.6<μ<6.8.

7 0

3 years ago

What is the trignometric ration for cos C? ____/____

tatiyna

cos $\alpha=\frac{adjacent}{hypotenuse}$

cosC = $\frac{45}{51}$

4 0

2 years ago

Read 2 more answers

What is the equation of the line that represents the horizontal asymptote of the function f(x)=25,000(1+0.025)^(x)?

posledela

Answer:

The answer is below

Step-by-step explanation:

The horizontal asymptote of a function f(x) is gotten by finding the limit as x ⇒ ∞ or x ⇒ -∞. If the limit gives you a finite value, then your asymptote is at that point.

$\lim_{x \to \infty} f(x)=A\\\\or\\\\ \lim_{x \to -\infty} f(x)=A\\\\where\ A\ is\ a\ finite\ value.\\\\Given\ that \ f(x) =25000(1+0.025)^x\\\\ \lim_{x \to \infty} f(x)= \lim_{x \to \infty} [25000(1+0.025)^x]= \lim_{x \to \infty} [25000(1.025)^x]\\=25000 \lim_{x \to \infty} [(1.025)^x]=25000(\infty)=\infty\\\\ \lim_{x \to -\infty} f(x)= \lim_{x \to -\infty} [25000(1+0.025)^x]= \lim_{x \to -\infty} [25000(1.025)^x]\\=25000 \lim_{x \to -\infty} [(1.025)^x]=25000(0)=0\\\\$

$Since\ \lim_{x \to -\infty} f(x)=0\ is\ a\ finite\ value,hence:\\\\Hence\ the\ horizontal\ asymtotes\ is\ at\ y=0$

5 0

2 years ago