The equivalent expression of 1/2 + 3c + 4/5 is 
<h3 /><h3>How to determine the equivalent expression?</h3>
The expression is given as:
1/2 + 3c + 4/5
Take the LCM of the expression

Evaluate the like terms

Hence, the equivalent expression of 1/2 + 3c + 4/5 is 
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<u>Given the 45-90-45 triangle property:</u>
Hyopentuse = 9√2, therefore:
Base = 9 + 9 = 18 m
Height = 9 m
Area of the top triangle = 1/2 (9) (18) = 81 m²
Area of the bottom triangle = 1/2(6)(18) = 54 m²
Tota area = 81 + 54 = 135 m²
Answer: 135 m²
Answer:
62 degrees
Step-by-step explanation:
Since lines i and k are parallel, angle b and h are interior angles and are equal to each other. Set up the equation by setting the two equal to each other.
8x-34=5x+2
Subtract 5x from both sides. (it cancels on the right side)
3x-34=2
Add 34 to both sides. (cancels on the left side)
3x=36
Divide both sides by 3.
x=12
Now plug it into either equation since they are equal. I'm gonna use the one for angle h so that it's less confusing.
5(12)+2
60+2
62
The measure of angle h is 62 degrees.
Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards