2(y-3)-y=-1 please help me with this one

In Newton's Law of cooling, fraction numerator d T over denominator d t end fraction equals k (T minus T subscript m )the consta

-BARSIC- [3]

Answer:

K-a Positive constant that depends on the area and nature of the surface of the body under consideration.

Step-by-step explanation:

Newtons law cooling describes the rate at which an exposed body changes temperature through radiation which is approximately proportional to the difference between the object’s temperature and its surroundings, provided the difference is small. The formula is given as:

$\frac{dT}{dt}=k(T-T_m)$

where,T- temperature at time t, $T_m$ is temperature of the surrounding and k- A Positive constant that depends on the area and nature of the surface of the body under consideration.

7 0

3 years ago

Please help me with all thank you

crimeas [40]

1. 7 : 07
2. 9 : 45
3. 6
4. 2 : 25
5. 8
6. 17

5 0

3 years ago

Find y, if x = 60.<br> A) 30° <br> B) 35° <br> C) 40° <br> D) 45°

MArishka [77]

The answer is 30°.
Rule: All three sides must add up to 180°.
Since A=60 and the side vertical to the angle which is 90° then side C would be C=90° and that adds up to 150°, so you can conclude that angle B is 30°.
I hope I helped!

7 0

3 years ago

Read 2 more answers

We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys

marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation

$\bar X=19.2$ represent the battery life sample mean

$\sigma=2.5$ represent the population standard deviation

$n=25$ sample size

$\mu_o =18$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:

Null hypothesis: $\mu = 18$

Alternative hypothesis: $\mu \neq 18$

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis: $\mu \leq 18$

Alternative hypothesis: $\mu > 18$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4$

4) P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=25-1=24$

Since is a two tailed test for parts I and II, the p value would be:

$p_v =2*P(t_{(24)}>2.4)=0.0245$

And for part III since we have a one right tailed test the p value is:

$p_v =P(t_{(24)}>2.4)=0.0122$

5) Conclusion

I. This finding is significant for a two-tailed test at .05.

Since the $p_v$ . We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the $p_v >\alpha$ . We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the $p_v >\alpha$ . We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0

3 years ago

A student wondered if more than 10% of students enrolled in an introductory Chemistry class dropped before the midterm. He noti

Ilia_Sergeevich [38]

Answer:

C.It is a one-tailed test since the alternative hypothesis states that the parameter is greater than the hypothesized value.

Step-by-step explanation:

Let p be the percentage of students enrolled in an introductory Chemistry class dropped before the midterm. Then null and alternative hypotheses are:

$H_{0}$ : p=10%

$H_{a}$ : p>10%

The alternative hypothesis states that the parameter is greater than the hypothesized value.

3 0

3 years ago