Question

Find the solutions to y = (x – 1)2 for x = –3, 0, and 3.

Answer 1

Answer:

if the 2 is the power of (x-1) here is ur answer

$y = (x - 1 ){}^{2} \\if \: x \: is \: \: equal \: to \: - 3 \\ y =( - 3 - 1) {}^{2} \\ y = ( - 4) {}^{2} \\ y = 16$

$if \: x = 0 \\ y = (0 - 1) {}^{2} \\y = ( - 1) { }^{2} \\ y = 1$

$if \: x = 3 \\ y = (3 - 1) {}^{2} \\ y = 2 { }^{2} \\ y = 4$

(-3,16) (0,1) (3,4)