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slamgirl [31]
3 years ago
7

Find the solutions to y = (x – 1)2 for x = –3, 0, and 3.

Mathematics
1 answer:
Harman [31]3 years ago
7 0

Answer:

if the 2 is the power of (x-1) here is ur answer

y = (x - 1 ){}^{2} \\if \: x \: is \: \: equal \: to \:  - 3  \\ y =(  - 3 - 1) {}^{2} \\  y = ( - 4) {}^{2} \\ y = 16

if \: x = 0 \\ y = (0 - 1) {}^{2}  \\y = (  - 1) { }^{2} \\ y = 1

if \: x = 3 \\ y = (3 - 1) {}^{2}  \\  y = 2 { }^{2}  \\ y = 4

(-3,16) (0,1) (3,4)

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