All categories

3 years ago

Explain how you know that in ?×6,273=6,273, the ? Will be 1

Mathematics

2 answers:

irakobra [83]3 years ago

8 0

Answer:

There would be 1.

Step-by-step explanation:

In real analysis,

1 is a multiplication identity,

Also, a real number after multiplying by the multiplicative identity gives the same number,

That is,

a . 1 = a = 1 . a ∀ a ∈ R

Since, 6273 is a real number,

Thus,

1 × 6273 = 6273

Hence, proved....

grigory [225]3 years ago

6 0

Anything more or less than 1 would result in a different outcome, and anything times 1 results in itself.

You might be interested in

Please help I’ll make you the brainiest

lakkis [162]

Answer:

X= 5, -2

Step-by-step explanation:

This would be the answer if you are looking to "solve"

6 0

2 years ago

I need to find the surface area and volume of all three figures. If you could provide what equations you used to I will be grate

Margarita [4]

Answer:

Part 1) Sphere The surface area is equal to $SA=196\pi\ m^{2}$ and the volume is equal to $V=\frac{1,372}{3}\pi\ m^{3}$

Part 2) Cone The surface area is equal to $SA=(16+4\sqrt{65})\pi\ units^{2}$ and the volume is equal to $V=\frac{112}{3}\pi\ units^{3}$

Part 3) Triangular Prism The surface area is equal to $SA=51.57\ mm^{2}$ and the volume is equal to $V=17.388\ mm^{3}$

Step-by-step explanation:

Part 1) The figure is a sphere

a) Find the surface area

The surface area of the sphere is equal to

$SA=4\pi r^{2}$

we have

$r=14/2=7\ m$ ----> the radius is half the diameter

substitute

$SA=4\pi (7)^{2}$

$SA=196\pi\ m^{2}$

b) Find the volume

The volume of the sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$r=14/2=7\ m$ ----> the radius is half the diameter

substitute

$V=\frac{4}{3}\pi (7)^{3}$

$V=\frac{1,372}{3}\pi\ m^{3}$

Part 2) The figure is a cone

a) Find the surface area

The surface area of a cone is equal to

$SA=\pi r^{2} +\pi rl$

we have

$r=4\ units$

$h=7\ units$

Applying Pythagoras Theorem find the value of l (slant height)

$l^{2}=r^{2} +h^{2}$

substitute the values

$l^{2}=4^{2} +7^{2}$

$l^{2}=65$

$l=\sqrt{65}\ units$

$SA=\pi (4)^{2} +\pi (4)(\sqrt{65})$

$SA=16\pi +4\sqrt{65}\pi$

$SA=(16+4\sqrt{65})\pi\ units^{2}$

b) Find the volume

The volume of a cone is equal to

$V=\frac{1}{3}\pi r^{2}h$

we have

$r=4\ units$

$h=7\ units$

substitute

$V=\frac{1}{3}\pi (4)^{2}(7)$

$V=\frac{112}{3}\pi\ units^{3}$

Part 3) The figure is a triangular prism

a) The surface area of the triangular prism is equal to

$SA=2B+PL$

where

B is the area of the triangular base

P is the perimeter of the triangular base

L is the length of the prism

Find the area of the base B

$B=\frac{1}{2} (2.7)(2.3)=3.105\ mm^{2}$

Find the perimeter of the base P

$P=2.7*3=8.1\ mm$

we have

$L=5.6\ mm$

substitute the values

$SA=2(3.105)+(8.1)(5.6)=51.57\ mm^{2}$

b) Find the volume

The volume of the triangular prism is equal to

$V=BL$

where

B is the area of the triangular base

L is the length of the prism

we have

$B=3.105\ mm^{2}$

$L=5.6\ mm$

substitute

$V=(3.105)(5.6)=17.388\ mm^{3}$

5 0

2 years ago

Slove:33/29=46/x. Try to find the answer.

Tju [1.3M]

Answer:

$x=40\frac{14}{33}$

Step-by-step explanation:

we have

$\frac{33}{29}=\frac{46}{x}$

Solve for x

Multiply in cross

$(33)(x)=(46)(29)$

Divide by 33 both sides (Division Property of Equality)

$x=46(29)/33$

$x=\frac{1,334}{33}$

Convert to mixed number

$x=\frac{1,334}{33}=\frac{1,320}{33}+\frac{14}{33}=40\frac{14}{33}$

5 0

2 years ago

2{ 3[9 + 4(7 -5) - 4]} can you guys help me

alexandr402 [8]

The answer is 78

Please see the attached picture for full solution

Hope it helps

Good luck on your assignment

8 0

2 years ago

Read 2 more answers

If f(x) = x2, then f(4) = 42 = 16. Find: a. f(1) b. f(-3) c. f(t)

icang [17]

Answer:

Step-by-step explanation:

f(x) = x²

f(4) = 4² = 16

f(1) = 1² = 1

f(-3) = -3² = 9

f(t) = t²

Always wise to us the ^ symbol to represent powers to avoid confusion

4^2 = 4² = 16

-3^2 = 9

t^2

if you are on a PC, the square symbol (²) can be typed by holding down the "alt" key while pressing and releasing "2","5","3" on the keypad, then release "alt". Unfortunately this does not work if you only have the row of numbers on the keyBoard to work with.

4 0

1 year ago