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RUDIKE [14]
3 years ago
10

Can orthocentre of an obtuse triangle lie below the triangle or it has to be above the triangle?

Mathematics
1 answer:
const2013 [10]3 years ago
5 0

Answer:

i think it has to be above the triangle

Step-by-step explanation:

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What is the slope-intercept equation for this line<br><br>(y= mx + b)? ​
lbvjy [14]

Answer:

y = -6x + 2

Step-by-step explanation:

To find the slope, you do rise/run. To get to one point from another, you move one unit to the right, and six units down.

Now to find the y-intercept, you need to identify the point that meets in the y-axis. That would be 2.

Hope this helps!

4 0
3 years ago
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C. Are 2b + b and 3b equivalent expressions​
Alecsey [184]

Answer: Yes

Step-by-step explanation:

Imagine you have b = 2.

Plug 2 into the equation 2b + b = 3b

You get: 2(2) + 2 = 3(2)

Which solves to be 6 = 6

As long as the variable is the same, in this case b, and they are to the same power, in this case ^1, you can combine them.

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3 years ago
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Solve x: 60 pts if u can figure it out and the first one gets brainiest answer
jenyasd209 [6]

Answer:

11.65

Step-by-step explanation:

3x+99x=102x

1188/102=11.65

6 0
2 years ago
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Find h if V = 30.45 ft3, l = 6.3 ft, and w = 2.5 ft.​
jok3333 [9.3K]

The height (h) of the rectangular prism is: 1.9 feet.

<h3>How to Find the Volume of a Rectangular Prism?</h3>

A rectangular prism has a length (l), height (h), and a width (w). The volume of the rectangular prism is calculated using the formula given as: V = (length)(width)(height).

Given the following parameters:

Volume of the rectangular prism = 30.45 ft^3,

Length (l) = 6.3 ft,

Width (w) = 2.5 ft.​

Height of the rectangular prism (h) = ?

Plug in the values

(6.3)(2.5)(h) = 30.45

15.75h = 30.45

15.75h/15.75 = 30.45/15.75

h ≈ 1.9 ft

Learn more about volume of rectangular prism on:

brainly.com/question/12917973

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4 0
2 years ago
Use matrix addition to solve this equation
REY [17]

Answer:

  • c11 = 8
  • c31 = 20
  • c22 = 14

Step-by-step explanation:

The sum of two matrices is the sum of corresponding terms.

\left[\begin{array}{ccc}3&1&0\\-1&2&4\\9&7&-2\end{array}\right] +\left[\begin{array}{ccc}5&2&4\\1&12&3\\11&3&-2\end{array}\right] =\left[\begin{array}{ccc}8&3&4\\0&14&7\\20&10&-4\end{array}\right]

8 0
3 years ago
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