Using arithmetic operations, rewrite this polynomial in standard, simplest form.
1 answer:
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Question:
Identify the sets that contain 2 as an element. (Check all that apply.)
Answer:
Step-by-step explanation:
Required
For which of the options is 2 an element
The elements of this set starts from 2, then 3 and continues as thus.
Hence: 2 is an element
From the given elements in the above set, 2 is not listed.
Hence: 2 is not an element of this set
Here, 2 is listed as an element, 2 is also listed as a subset.
Since 2 is listed as an element, then 2 is an element of the set.
Here, 2 is listed as a subset of {2} and also as a subset of subset of {{2}}.
Since 2 is not listed as an element itself, then 2 is not an element of the set.
Here, 2 is listed as a subset of {2} and also as a subset of subset of {2,{2}}. This set only contains subsets, i.e. 2 is not listed as a direct element of the set.
Hence: 2 is not an element of the set
Here, 2 is listed as a subset of subset of {{2}}. This set only contains subsets, i.e. 2 is not listed as a direct element of the set.
Hence: 2 is not an element of the set
Answer:
C, D, E, F
Step-by-step explanation:
Remember y=mxb?
m is slope and b is y-intercept
so y=2/7x-9
Remember that slope is RISE/RUN so for every 2 squares that you go up, you go 7 squares to the right.
Also remember that since your graph is going thru your Cartiesian Plane in quadrent 4, your y value in your ordered pairs will most probably be a negative.
Please see the image to help you viualize this.
