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3 years ago

Using arithmetic operations, rewrite this polynomial in standard, simplest form.

1 answer:

7 0

(3x2 + 9x + 6) − (8x2 + 3x − 10) + (2x + 4)(3x − 7)

First distribute the (2x+4)(3x-7) to get 6x2-2x-28
After this just add the like terms for all parts of the expression.
(3x2-8x2+6x2)+(9x-3x-2x)+(6+10-28)
x2+4x-12

So you answer is x2+4x-12

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I need some help pls thx

Tresset [83]

Answer:

Graph A represents a function

Step-by-step explanation:

in a function every input will have its own specific output.

8 0

3 years ago

I run a 10km race in 56 minutes.what is my average speed in kilometres per minute

Luden [163]

Hey there! I'm happy to help!

You ran a 10 kilometer race in 56 minutes (good job!). To find how much you ran in 1 minute, you simply divide by 56.

10/56=0.178571428

Therefore, you ran around 0.18 km/minute.

Have a wonderful day! :D

7 0

3 years ago

A company that has 350000 shares declares an annual gross profit of $2450665, pays 18.5% of this in tax, and reinvests 25% of th

podryga [215]

Gross profit, G = $2450665

Tax, t=18.5%

reinvestment, r = 25%

Total dividends

= G(1-t)(1-r)

=2450665*(1-0.185)(1-0.25)

=1497968.98

Dividend per share

=1497968.98/350000

=4.280

Earnings per share

EPS = Net profit / number of shares

= 2450665(1-0.185)/350000

=5.7065

Current price = 43.36

P/E ratio

= Current price/EPS

= 43.36/5.7065

= 7.598

=7.6 to one decimal place.

8 0

3 years ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

monitta

Answer:

a) n =1623

b) $ME=2.0538\sqrt{\frac{0.21 (1-0.21)}{1623}}=0.0208$

Step-by-step explanation:

1) Notation and definitions

$n$ random sample taken

$\hat p=0.19$ estimated proportion of customers are not satisfied with the service provided by the local dealer

Confidence =0.96 or 96%

Me= 0.02 represent the margin of error

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 96% of confidence, our significance level would be given by $\alpha=1-0.96=0.04$ and $\alpha/2 =0.02$ . And the critical value would be given by: