I stink at math please help me!

Mathematics

1 answer:

IceJOKER [234]3 years ago

6 0

Only 0.15 or 3/20 of voters were eligible for Shelly. Only 0.3125 or 5/16 of voters were eligible for Morgan.

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Which scatterplot does NOT suggest a linear relationship between x and y. Look AT IMAGE

Afina-wow [57]

Answer:

Graph C

Step-by-step explanation:

It is Graph C because the points are majorly curved, while the rest of the lines are linear because they are straight.

Hope this helps! :D

- Luna

7 0

3 years ago

Solve the equation or formula for the indicated variable.

alex41 [277]

Subtract 3 both sides first. R-3=ts²

next, divide both sides by t, (R-3)/t=s²

finally, take the square root of both sides

√(R-3)/t = s. 2nd choice.

3 0

3 years ago

Read 2 more answers

(cotx+cscx)/(sinx+tanx)

Butoxors [25]

Answer: $\bold{\dfrac{cot(x)}{sin(x)}}$

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

$\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)$

$\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)$

$\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}$

6 0

3 years ago

Which equation describes the relationship expressed in the table?

Arada [10]

Y=(1/3)*x is the correct answer.

1/3 of -3 is -1

1/3 of 0 is 0

1/3 of 6 is 2

3 0

3 years ago

Help with this question anyone?

Art [367]

Adding 49 will explain it properly just do that and you will get the answers

6 0

3 years ago