1. Huwa fupi - hadithi fupi nyingi huhitaji kuunganishwa pamoja kuunda kitabu kimoja. 220
So using a(2)=0 we can first solve for k by substituting t for 2
0 = (2-k)(2-3)(2-6)(2+3)
0 = (2-k)(-1)(-4)(5)
0 = (2-k)20
0 = 40 - 20k
-40 = -20k
k = 2
The next step would be to find all the 0s of a.
0 = (t-2)(t-3)(t-6)(t+3)
T = 2,3,6,-3
Then we find the product
2x3x6x-3 = -108
Since the problem asks for the absolute value, the answer is positive 108
Answer:
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The equation 
shows that the diagonals are congruent perpendicular bisectors.
The vertices of the square are given as:
- c = (1,1)
- d = (3,1)
- e =(3,-1)
- f = (1,-1)
<h3>How to determine the
congruent perpendicular bisectors.</h3>
Start by calculating the slope of diagonal ce using:
So, we have:
Next, calculate the slope of diagonal df using:
So, we have:
The slopes of both diagonals are:
By comparing both slopes, we have:
i.e.
Hence, shows that the diagonals are congruent perpendicular bisectors.
Read more about perpendicular bisectors at:
brainly.com/question/11006922
