5. How many subnets are possible in a network with a /19 CIDR?
1 answer:
Answer:
8192
Explanation:
The question is pretty general. However, I will try to explain it in my way.
An IP address consists of 32 bit. It is always divided in two portion, net id and host id. Net id is a kind of identification while host id bits includes the possible number of host in the network of specific id.
My assumption is that you are using the classless CIDR.
In that case the first 19 bits would be the net id or identification of the network. Therefore, the net id would be 11111111.11111111.11100000.00000000
Or 255.255.224.00
Now, if we want to add a subnet in this IP, we can utilize the remaining bits from the host id. We are left with 13 bits in host id so the number of subnets will be depending on how many bits we will be using in host id with
.
In this equation, x represents the number of bits used to create the subnets.
So, maximum number of subnets would be
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Answer:
see explaination
Explanation:
Python version : 2.7
Python program to read an input file with specified number of records to read
and output the top 3 ranked actors
The format of input file:
<number of records to read>
<actor_name>,<movie_name>
<actor_name>,<movie_name>
....
'''
#define the file name
filename = 'actors_movies.txt'
# create an empty dictionary to contain the actor name as key and number of movies they have acted as value
actors_movie_count = {}
# open the flie
fp = open(filename)
line = fp.readline() # read the first line
count = int(line)
i = 0
# loop to read count number of lines from file
while i < count:
line = fp.readline() # read a line
data = line.split(",") # split the input data into list of strings using comma as the delimiter
# check if actor name is present in the dictionary, then add 1 to its value
# strip is used to remove any leading or trailing space
if data[0].strip() in actors_movie_count:
actors_movie_count[data[0].strip()] += 1
else: # else insert a new record with actor name as its key and 1 as value
actors_movie_count[data[0].strip()] = 1
i += 1
# close the file
fp.close()
# get the list of names of actors and list of number of movies they have acted
actors = actors_movie_count.keys()
num_movies = actors_movie_count.values()
# loop to sort the actors list and num_movies list in descending order of count of movies
for i in range(len(num_movies)-1):
max = i
for j in range(i+1,len(num_movies)):
if num_movies[j] > num_movies[max]:
max = j
if max != i:
actors[max], actors[i] = actors[i], actors[max]
num_movies[max], num_movies[i] = num_movies[i], num_movies[max]
# rank the actors to add top 3 ranked actors to rank_actors list
rank = 1
rank_actors = []
# add the first actor to list
rank_actors.append(actors[0])
# loop from second to end of actors list
for i in range(1,len(actors)):
# if this actor has same number of movies as the actor before him, then assign same rank
if num_movies[i] == num_movies[i-1]:
# if rank <= 3, add the actor in rank_actors list
if rank <= 3:
rank_actors.append(actors[i])
else: # rank > 3, exit the loop
break
else: # assign 1 more rank that the previous
rank += 1
# if rank <= 3, add the actor in rank_actors list
if rank <= 3:
rank_actors.append(actors[i])
else: # rank > 3, exit the loop
break
# loop to display the top 3 ranked actors
for actor in rank_actors:
print(actor)
#end of program
see attachment for the program screenshot and output
