Answer:
Whenever you assume values, try and make them as accurate as possible i.e. I am looking for consecutive even numbers so I will assume the values to be (2n - 2), 2n and (2n + 2)
s2−r2−q2=(2n+2)2−(2n)2−(2n−2)2s2−r2−q2=(2n+2)2−(2n)2−(2n−2)2
You get: 4n (4 - n)
So the solution must have 4 as a factor, which we see all options do.
To get -20, n(4-n) must be (-5). It will happen when n = 5.
To get 0, n = 0
To get 12, n(4-n) must be 3. It will happen when n = 3
To get 16, n(4-n) must be 4. It will happen when n = 2
There is no way n(4-n) could be 2 if n is an integer so 8 is not possible.Step-by-step explanation:
Answer:
Not sure about part B but A is 13 and i'm not sure what you mean by round it to the nearest hundredth place value wouldn't that be 300
Step-by-step explanation:
Answer:
1,260 i believe
Step-by-step explanation:
