4 years ago

If AB:BC is 3:11 solve for x

1 answer:

8 0

If AB:BC is 3:11 solve for x the answer is 9

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GenaCL600 [577]

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dolphi86 [110]

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Rudik [331]

Answer:

The standard form of the given expression is $- (\frac{4}{5})x + y + (\frac{17}{5}) = 0$

Step-by-step explanation:

Here, the given expression is $y + 1 = \frac{4}{5} (x-3)$

Now, the Standard Form of the equation is ax + by + c = 0

Solving this, we get:

$y + 1 = \frac{4}{5} (x-3) \implies y + 1 = (\frac{4}{5})x - \frac{12}{5}$

⇒ $y + 1 - (\frac{4}{5})x + (\frac{12}{5}) = 0$

or, $y - (\frac{4}{5})x + (\frac{12}{5} + 1 )= 0 \implies y - (\frac{4}{5})x + (\frac{12+ 5}{5}) = 0$

⇒ $y - (\frac{4}{5})x + (\frac{17}{5}) = 0$

Hence, the standard form of the given expression is $- (\frac{4}{5})x + y + (\frac{17}{5}) = 0$

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lesya692 [45]

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lorasvet [3.4K]

The answer is $68.

Hope this helps!!! :)

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