3 years ago

Please help asap 25 pts

1 answer:

4 0

$\dfrac{6x-24}{16-x^2}=\dfrac{6(x-4)}{4^2-x^2}=\dfrac{6(x-4)}{-(x^2-4^2)}\\\\=\dfrac{6(x-4)}{-(x-4)(x+4)}\\\\\boxed{Answer:\ -\dfrac{6}{x+4}}$

$Used:\ a^2-b^2=(a-b)(a+b)$

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