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3 years ago

15

What is the correct plural form of "una bebida popular"?

2 answers:

const2013 [10]3 years ago

8 0

Answer- I am Spanish so this was easy to do. But I can't help noticing that c and d are the same answer so both are correct.

Olegator [25]3 years ago

6 0

The answer is C!!!! hope this helps!

You might be interested in

In the 2017 fiscal year, the state of Alaska received $8.2 billion In revenues and had $7.2 billion in expenditures. What percen

konstantin123 [22]

To figure this out you can do 7.2/8.2, because you are trying to figure out how much of the total was used, and percentages would not be more than 100%. Doing this you would get ~.878. To convert this to a percent, you would just multiply it by 100, which would give you 87.8%. The question states to round to the nearest whole percent, leaving you with 88%. This means that 88% of the revenue was spent.

Hope that helped, don't be shy to comment on this if you have any questions about my explanation :)

8 0

3 years ago

What percent of 2.5 of 0.3

Alona [7]

It would be 12% because .3 divided by 2.5 is .12 which is equivalent to 12%

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B

riadik2000 [5.3K]

Let

$S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n$

where we assume |r| < 1. Multiplying on both sides by r gives

$r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}$

and subtracting this from $S_n$ gives

$(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}$

As n → ∞, the exponential term will converge to 0, and the partial sums $S_n$ will converge to

$\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}$

Now, we're given

$a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a$

$a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}$

We must have |r| < 1 since both sums converge, so

$\dfrac{15}a = \dfrac1{1-r}$

$\dfrac{150}{a^2} = \dfrac1{1-r^2}$

Solving for r by substitution, we have

$\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)$

$\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}$

Recalling the difference of squares identity, we have

$\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}$

We've already confirmed r ≠ 1, so we can simplify this to

$\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15$

It follows that

$\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12$

and so the sum we want is

$ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}$

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0

2 years ago

Is P 90 degrees from the origin, Q 180 degrees from the origin, and R 270 degrees from the origin?

krek1111 [17]

Answer:

Step-by-step explanation:

(x,y)→(-x,-y) (180° about the origin)

1.p(-3,2) ,in the second quadrant

P(-2,-3) is in 4th quadrant.

in the clockwise it is rotation of 270° about the origin.

2.

Q(-4,-5) is in 4th quadrant.

Q(4,5) is in 1st quadrant.

so it is 180° rotation in the clockwise direction.

3.

R(1,7) is in 1st quadrant.

R(7,-1) is in 4th quadrant.

Hence it is 90° rotation about the origin in clockwise direction.

4 0

3 years ago

Give the sum in simplest form: 2x/w + y/w

kupik [55]

Answer:

$\frac{2x+y}{w}$

5 0

3 years ago