Sin B = A. 5/13 B. 12/13 C. 5/12 D. 13/12

WILL MARK BRAINLIEST ' IF YOU DONT KNOW DONT ANSWER

Soloha48 [4]

Answer: A) Alternate Exterior

Step-by-step explanation:

Let's find out the defenition of alternate exterior; "If a pair of parallel lines are cut by a transversal line, then the alternate exterior angles are congruent".

I hope this helps!

8 0

3 years ago

Find the range of the following peicewise functiom

sasho [114]

answer is [0,11)

f(x) = x+4 is the first function

We plug in -4 for x in f(x) = x+4

f(-4) = -4 + 4 = 0

So the graph starts at (-4,0)

Now plug in 3 for x in f(x) = x+4

f(3) = 3 + 4 = 7

So the first function ends at (3,7)

Second function is f(x) = 2x - 1

We plug in 3 for x in f(x) = 2x-1

f(3) =2(3)-1 = 5

So the second graph starts at (3,5)

We plug in 6 for x in f(x) = 2x-1

f(6) =2(6)-1 = 11

So the second graph ends at (6,11)

3<=x<6 so 6 is excluded from x

The range of the following piece wise function is 0 to 11

answer is [0,11)

7 0

3 years ago

Read 2 more answers

Five years after 650 high school seniors graduated, 400 had a college degree and 310 were married. Half of the students with a c

DedPeter [7]

Answer:

The probability that a student has a college degree or is not married is 0.8308.

Step-by-step explanation:

The information provided is:

Total number of high school seniors (N) = 650.

Number of seniors with a college degree (n (C)) = 400.

Number of seniors who were married, (n (M)) = 310.

Consider the Venn diagram below.

The probability of an event, say E, is the ratio of the favorable outcomes of E to the total number of outcomes of the experiment.

That is,

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes of E

N = total number of outcomes of the experiment.

The probability of the union of two events is:

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=\frac{n(A)+n(B)-n(A\cap B)}{N}$

Compute the probability that a student has a college degree or is not married as follows:

$P(C\cup M^{c})=\frac{n(C)+n(M^{c})-n(C\cap M^{c})}{N}$

From the Venn diagram:

n (C) = 400

n ( $M^{c}$ ) = N - n (M) = 650 - 310 = 340

n (C ∩ $M^{c}$ ) = 200

The value of P (C ∪ $M^{c}$ ) is:

$P(C\cup M^{c})=\frac{n(C)+n(M^{c})-n(C\cap M^{c})}{N}=\frac{400+340-200}{650}=0.83077\approx0.8308$

Thus, the probability that a student has a college degree or is not married is 0.8308.

6 0

3 years ago

Read 2 more answers

Determine the vertex form of g(x) = x^2 + 2x – 1. Which graph represents g(x)?

nataly862011 [7]

Answer:

Graph D

Step-by-step explanation:

Move the constant to the opposite side of the equation and group terms that include the same variable.

g(x) + 1 = x^2 + 2x

Finish the square. Remember to keep the equation balanced by using the same constants on both sides.

g(x) + 1 + 1 = x^2 + 2x + 1

g(x) + 2 = x^2 + 2x + 1

Rewrite as perfect squares

g(x) + 2 = (x + 1)^2

Equation in vertex form:
g(x) = (x + 1)^2 - 2

The vertex:

(-1, -2)

* This a minimum *

(Parabola open upward)

3 0

2 years ago

A local school requires 3 teachers for every 93 students. Which equation represents this relationship, where t is the number of

alexira [117]

Answer:

t = 31s

Step-by-step explanation:

................

7 0

3 years ago

Sin B =A. 5/13B. 12/13C. 5/12D. 13/12