Answer: the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
Step-by-step explanation:
Given data;
lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min
hence, height = 1 / ( 52.0 - 50.0) = 1 / 2
now the probability that the class length is between 50.8 and 51 min = ?
P( 50.8 < X < 51 ) = base × height
= ( 51 - 50.8) × 1/2
= 0.2 × 0.5
= 0.1 ≈ 10%
therefore the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
This does not look easy to factor, so I'd suggest using the quadratic formula:
-1 plus or minus sqrt( 1-4(3)(-5) )
x = -----------------------------------------------
2*3
-1 plus or minus sqrt(61)
= ------------------------------------
6
Thus, there are 2 real, unequal, irrational roots / solutions.
First do (30×20)/2 + 20×25 + 35×42 + (42×25)/2
it should give you a total of 2795 cm
Answer:
Logan is 45 feet from second base.
Step-by-step explanation:
If you divide 90 by 2 because is 1/2 away then it would be 45
