$q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}$

8 0

3 years ago

Calculate the expected value of playing a lottery ticket game where each ticket costs $5, and the chance of having winning ticke

Amanda [17]

Answer:

$4895

Step-by-step explanation:

P(winning) = 1 / 1000000 = 0.000001

P(not winning) = 1 - 1/1000000 = 0.999999

Winning amount = 4,900,000,000 - 5 = 4899999995

Amount lost = - 5

__ X: - 5 _________ 4899999995

P(X) : 0.999999 ___ 0.000001

Expected value E(x) = Σx * p(x)

E(x) = - 5(0.999999) + 4899999995(0.000001)

E(x) = - 4.999995 + 4899.999995

E(x) = 4895

Hence, expected value is 4895

6 0

3 years ago

Use multiplication to find all the whole number ratios equivalent to 5 to 11

natka813 [3]

Answer:

thxfor free points

Step-by-step explanation:

8 0

3 years ago