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3 years ago

Simplify the expression (3-4i)(2+3i)

Mathematics

2 answers:

azamat3 years ago

7 0

3×2=6
3×3i= 9i
-4i×2= -8i
-4i×3i= -12i^2

the answer would be 6+i-12i^2

I hope this helps ~~♡♡ Chyna

Molodets [167]3 years ago

7 0

Answer:

6-8i+9i-12i^2= <u>6 + i - 12i^2</u>

Step-by-step explanation:

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- Eight mechanics all earning $16 an hour met for a half

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Answer:

The 30-minute meeting of eight mechanics being paid $16 an hour, costed the garage $64!

Step-by-step explanation:

First, identify what you know:

1) A single mechanic is paid $16 an hour.

2) Eight mechanics, being paid $16 an hour, met.

3) The meeting lasted 30 minutes, or half an hour.

If a mechanic makes $16 dollars in one hour (60 min), how much would they make in half an hour? Since they worked for half an hour, they'd make half an hour wage!

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3 years ago

Which description is correct for the polynomial −5x^3−4x+1 ?

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The answer is cubic trinomial because the highest exponent is 3 which makes it a cubic function and there are 3 terms which makes it a trinomial

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4 years ago

4x – y = 7 3y – 12x = –21

Elis [28]

Answer:

y= 4x − 7 or 0=0

Step-by-step explanation:

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3 years ago

Read 2 more answers

An article in Technometrics (Vol. 19, 1977, p. 425) presents the following data on the motor fuel octane ratings of several blen

Slav-nsk [51]

Answer:

$Median = 90.4$

$Q_1 = 88.6$

$Q_3 = 92.2$

Step-by-step explanation:

Given

The above data

Required

- A stem and leaf display

- The median

- The quartiles

First, determine the range of the data

$Smallest = 83.4$

$Highest = 100.3$

Next, group each dataset base on common whole numbers.

So, we have:

$83.4$

$84.3\ 84.3$

$85.3$

$86.7\ 86.7\ 86.7$

$87.4\ 87.5\ 87.6\ 87.7\ 87.8\ 87.9$

$88.2\ 88.3\ 88.3\ 88.3\ 88.4\ 88.5\ 88.5\ 88.6\ 88.6\ 88.7\ 88.9$

$89.0\ 89.2\ 89.3\ 89.3\ 89.6\ 89.7\ 89.8\ 89.8\ 89.9\ 89.9$

$90.0\ 90.1\ 90.1\ 90.1\ 90.3\ 90.4\ 90.4\ 90.4\ 90.5\ 90.6\ 90.7\ 90.8\ 90.9$

$91.0\ 91.0\ 91.0\ 91.1\ 91.1\ 91.1\ 91.2\ 91.2\ 91.2\ \ 91.5\ 91.6\ 91.6\ 91.8\ 91.8$

$92.2\ 92.2\ 92.2\ 92.3\ 92.6\ 92.7\ 92.7\ 92.7$

$93.0\ 93.2\ 93.3\ 93.3\ 93.4\ 93.7$

$94.2\ 94.2\ 94.4\ 94.7$

$96.1\ 96.5$

$98.8$

$100.3$

Next, we construct the stem and leaf plot.

The whole numbers will be the stem while the decimal parts will be the leaf.

So, we have:

$\begin{array}{ccc}{Stem} & {} & {Leaf} & {83} & {|} & {.4} & {84} & {|} & {.3\ .3} & {85} & {|} & {.3} & {86} & {|} & {.7\ .7\ .7} & {87} &{|} & {.4\ .5\ .6\ .7\ .8\ .9} & {88} & {|} & {.2\ .3\ .3\ .3\ .4\ .5\ .5\ .6\ .6\ .7\ .9} &{89} & {|} & {.0\ .2\ .3\ .3\ .6\ .7\ .8\ .8\ .9\ .9} & {90} & {|} &{.0\ .1\ .1\ .1\ .3\ .4\ .4\ .4\ .5\ .6\ .7\ .8\ .9} & {91} &{|}&{.0\ .0\ .0\ .1\ .1\ .1\ .2\ .2\ .2\ .5\ .6\ .6\ .8\ .8} &{92} &{|} &{.2\ .2\ .2\ .3\ .6\ .7\ .7\ .7} \ \end{array}$

$\begin{array}{ccc} {93} & {|} & {.0\ .2\ .3\ .3\ .4\ .7} & {94} &{|} & {.2\ .2\ .4\ .7} &{96} & {|} & {.1\ .5} & {98} & {|} & {.8} & {100} &{|} &{.3} \ \end{array}$