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Svetach [21]
3 years ago
11

If I got 121 questions and 99 wrong on a test what is the percentage that I got wrong?

Mathematics
2 answers:
wel3 years ago
5 0

Answer:

Hmm probably 22%

Step-by-step explanation:

sorry if wrong i forgot percentages

sergij07 [2.7K]3 years ago
4 0
If there is 121 question on the test and you got 99 wrong that would be 18% I think
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PQ is rotated 180 degrees clockwise about P. What are the coordinates of P' and Q'?
Salsk061 [2.6K]

The co ordinates of P' is (-7,-2) and Q' is (-16, -8)

<u><em>Explanation</em></u>

PQ is rotated 180 degrees clockwise about P. It means <u>P and P' are the same points</u>.

According to the graph, the coordinates of P is (-7, -2) and  Q is (2, 4)

When PQ is rotated 180 degrees clockwise about P, then <u>P or P' will be the mid-point of Q and Q' </u>

Suppose, the co ordinate of Q' is (x, y)

Now according to the mid-point formula, the coordinate of P or P' will be: (\frac{x+2}{2},\frac{y+4}{2}) , which is actually at (-7, -2)

Thus.....

\frac{x+2}{2}=-7\\ \\ x+2=-14\\ \\ x= -16\\ \\ and\\ \\ \frac{y+4}{2}= -2\\ \\ y+4= -4\\ \\ y= -8

So, the co ordinates of P' is (-7,-2) and Q' is (-16, -8)

6 0
2 years ago
Solve for x.<br><br><br><br> 5+x+(−2)=−8
levacccp [35]
5+х-2+8=0
х+5-2+8=0
х+11=0
х=0-11
х=-11
7 0
3 years ago
A car insurance company has determined that 9% of all drivers were involved in a car accident last year. among 14 drivers living
andriy [413]

The probability of getting 3 or more who were involved in a car accident last year is 0.126.

Given 9% of the drivers were involved in a car accident last year.

We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.

We have to use binomial theorem which is as under:

nC_{r}p^{r} (1-p)^{n-r}

where p is the probability an r is the number of trials.

Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]

=1-{14C_{0}0.9^{0} (0.1)^{14} +14C_{1} (0.9)^{1} (0.1)^{13} +14C_{2} (0.9)^{2} (0.1)^{12}}

=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}

=1-{0.2670+0.3654+0.2358}

=1-0.8682

=0.1318

Among the options given the nearest is 0.126.

Hence the probability that 3 or more are involved in the accident is 0.126.

Learn more about probability at brainly.com/question/24756209

#SPJ4

7 0
1 year ago
Pair of shoes usually sells for $70. If the shoes are 40% off, and sales tax is 5%, what is the total price of the shoes, includ
Illusion [34]

Answer:

$44.10

Step-by-step explanation:

The sale price of the shoes is (1.00-0.40)($70), or $42.

The final price, including tax, is (1.00 + 0.05)($42), or $44.10.

4 0
3 years ago
Please Help!! Will pick brainliest!
leonid [27]
Small circle 2/4 = 1/2 and the big circle is 3/5 i hope this is correct. im truly sorry if this was wrong
7 0
3 years ago
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