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3 years ago

LAB: Even/odd values in an array

Computers and Technology

2 answers:

forsale [732]3 years ago

7 0

Answer:

integers=[]

while True:

number=int(input())

if number<0:

break

integers.append(number)

print("",min(integers))

print("",max(integers))Explanation:

Masja [62]3 years ago

4 0

Answer:

#include <stdio.h>
bool IsArrayEven(int inputVals[], int numVals){
int i;
for(i = 1; i < numVals; i++){
if(inputVals[i] % 2 != 0){
return false;
}
}
return true;
}
bool IsArrayOdd(int inputVals[], int numVals){
int i;
for(i = 1; i < numVals; i++){
if(inputVals[i] % 2 == 0){
return false;
}
}
return true;
}
int main()
{
int my_input[] = {5, 2, 4, 6, 8, 10};
if(IsArrayEven(my_input)){
printf("all even");
}else if(IsArrayOdd(my_input)){
printf("all odd");
}else{
print("not even or odd");
}
}

Explanation:

Firstly, write two functions to check if the input array is all even or all odd (Line 3-22). The key idea is to use modulus operator to check if a number % 2 equal to 0, it is an even number, if not, it is an odd. So long as one of the number is odd in the isArrayEven function, the function shall return false (Line 7). If no odd value detected, it return true (Line 11). The similar code logic is applied to isArrayOdd function too.

Then, we can call the two functions sequentially in the main program. If isArrayEven function return true, it display all even message (Line 28-29). If odd, display all odd (Line 30 -31). If neither, display not even or odd (Line 32-33).

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Write function d2x() that takes as input a nonnegative integer n (in the standard decimal representation) and an integer x betwe

Rufina [12.5K]

Answer:

The function in Python is as follows:

def d2x(d, x):

if d > 1 and x>1 and x<=9:

output = ""

while (d > 0):

output+= str(d % x)

d = int(d / x)

output = output[::-1]

return output

else:

return "Number/Base is out of range"

Explanation:

This defines the function

def d2x(d, x):

This checks if base and range are within range i.e. d must be positive and x between 2 and 9 (inclusive)

if d >= 1 and x>1 and x<=9:

This initializes the output string

output = ""

This loop is repeated until d is 0

while (d > 0):

This gets the remainder of d/x and saves the result in output

output+= str(d % x)

This gets the quotient of d/x

d = int(d / x) ----- The loop ends here

This reverses the output string

output = output[::-1]

This returns the output string

return output

The else statement if d or x is out of range

else:

return "Number/Base is out of range"

4 0

3 years ago

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Goshia [24]

Answer:

Answer explained below

Explanation:

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6 0

3 years ago

knowledge contributes vitally to the development of __________ memory, or recollections of personally experienced events that oc

Anettt [7]

Answer:

Episodic

Explanation:

Episodic memory are memory that enables a person to remember most important event that happen to them, which are unique to them and are tied to a specific time and place.

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Example:

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5 0

3 years ago

In this lab, you will build a system for package delivery services that provides different shipping options with specific price.

Alex73 [517]

Answer:

See explaination

Explanation:

#include <iostream>

#include <string.h>

using namespace st d;

class Package

{

protected:

//sender properities

char sname[10],saddress[50],scity[20],sstate[20];

long int szip;

//Receiver properities

char rname[10],raddress[50],rcity[20],rstate[20];

long int rzip;

//additonal datamembers

float weight,cost;

public:

Package() //Default constructor

{

strcpy(sname,"");strcpy(saddress,"");strcpy(scity,"");

strcpy(sstate,"");szip=0;

strcpy(rname,"");strcpy(raddress,"");strcpy(rcity,"");

strcpy(rstate,"");rzip=0;

weight=cost=0;

}

Package(char sn[10],char sa[50],char sc[20],char ss[20],long int sz,char rn[10],char ra[50],char rc[20],char rs[20],long int rz,float w,float c) //Constructor with parameter

{

strcpy(sname,sn);strcpy(saddress,sa);strcpy(scity,sc); //copying each parameter value to data member

strcpy(sstate,ss);szip=0;

strcpy(rname,rn);strcpy(raddress,ra);strcpy(rcity,rc);

strcpy(rstate,rs);rzip=0;

weight=w;cost=c;

}

float calculateCost() //calculating cost

{

return weight*cost;

}

};

class TwoDayPackage:public Package //Inheritance

{

float flatfee;

public:

TwoDayPackage(char sn[10],char sa[50],char sc[20],char ss[20],long int sz,char rn[10],char ra[50],char rc[20],char rs[20],long int rz,float w,float c,float ff) //Constructor with parameter

{

Package(sn,sa,sc,ss,sz,rn,ra,rc,rs,rz,w,c); //calling super class constructor

flatfee=ff; //copy last parameter

}

float calculateCost() //redefined calculateCost function

{

return (weight*cost)+flatfee; //return total cost

}

};

class OverNightPackage:public Package //Inheritance

{

float addfee;

public:

OverNightPackage(char sn[10],char sa[50],char sc[20],char ss[20],long int sz,char rn[10],char ra[50],char rc[20],char rs[20],long int rz,float w,float c,float a f) //constructor with parameter

{

Package(sn,sa,sc,ss,sz,rn,ra,rc,rs,rz,w,c); //calling super class constructor

addfee=a f; //copy last parameter

}

float calculateCost() //redefined calculateCost function

{

return (weight*cost)+addfee; //calculating total cost

}

};

int main()

{

Package package1("lou brown","1 main st","boston","ma",11111,"mary smith","7 elm st","new york","ny",22222,8.5,0.5); //creating objects

TwoDayPackage package2("lisa klein", "5 broadway", "somerville", "ma", 33333, "bob george", "21 pine rd", "cambridge", "ma", 44444, 10.5, .65, 2.0 );

OverNightPackage package3 ("ed lewis", "2 oak st", "boston", "ma", 55555, "don kelly", "9 main st", "denver", "co", 66666, 12.25, .7, .25 );

cout<<"\nPackage Cost : "<<package1.calculateCost(); //calling each cost

cout<<"\nTwoDay Package Cost : "<<package2.calculateCost();

cout<<"\nOvernight Package Cost : "<<package3.calculateCost();

return 0;

}

8 0

4 years ago

Write a recursive function that takes a non-negative integer as an argument and displays the same number in reverse order (i.e.

avanturin [10]

Answer:

Following are the program in C++ language

#include<iostream> // header file

using namespace std; // namespace std

int reverse(int n1); // function prototype

int main() // main function()

{

int num; // Variable declaration

cout << "Enter the number" << endl;

cin >> num; // Read the number bu the user

cout<<"After Reverse the digit:\n";

int res= reverse(num); // calling function reverse

cout<<res; // display

}

int reverse(int n1) // function definition of reverse

{

if (n1<10) // checking the base condition

{

return n1;

}

else

{

cout << n1 % 10; // Printed the last digit

return reverse(n1/10); // calling itsself

}

Output:

Enter the number:

76538

After Reverse the digit:

83567

Explanation:

Following are the description of the program

In the main function read the number by user in the "num" variable of int type.

Calling the reverse and pass that "num" variable into it.

After calling the control moves to the body of the reverse function.In this function we check the two condition

1 base condition

if (n1<10) // checking the base condition

{

return n1;

}

2 General condition

else

{

cout << n1 % 10; // Printed the last digit

return reverse(n1/10); // calling itsself

}

Finally return the reverse number and display them into the main function.

5 0

4 years ago