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ss7ja [257]
4 years ago
5

Kevin and Randy MUISE have a jar containing 51 coins all of which are either quarters or nickels the total value of the coins in

the jar is $9.55 how much of each type of coin do they have
Mathematics
1 answer:
frez [133]4 years ago
3 0

Answer:

Inside the jar there's 16 nickels and 35 quarters.

Step-by-step explanation:

Since there are only nickels and quarters in the jar, the sum of the number of nickels and the number of quarters inside it must be equal to the total number of coins in the jar. So

nickels + quarters = 51

We know the total value inside the jar, to obtain this value we must multiply the amount of each kind of coin by it's value and sum it. So we have:

0.05*nickels + 0.25*quarters = 9.55

We now have two equations and two variables, so we can solve them as follows:

nickels + quarters = 51

0.05*nickels + 0.25*quarters = 9.55

From the first equation:

nickels = 51 - quarters

0.05*(51 - quarters) + 0.25*quarters = 9.55

2.55 - 0.05*quarters + 0.25*quarters = 9.55

0.2*quarters = 9.55 - 2.55

quarters = 7/0.2 = 35

nickels = 51 - 35 = 16

Inside the jar there's 16 nickels and 35 quarters.

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