Answer:
It's 8
Step-by-step explanation:
![16 ^{ \frac{3}{4} } = \sqrt[4]{16 ^{3} } = \sqrt[4]{2 ^{4 \times 3} } = 2^{ \frac{12}{4} } = 2^{3} = 8](https://tex.z-dn.net/?f=%2016%20%5E%7B%20%5Cfrac%7B3%7D%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B16%20%5E%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B2%20%5E%7B4%20%5Ctimes%203%7D%20%7D%20%3D%202%5E%7B%20%5Cfrac%7B12%7D%7B4%7D%20%7D%20%20%20%3D%202%5E%7B3%7D%20%20%3D%208)
Answer:
y=-2x+2
Step-by-step explanation:
okay?.......................
Answer:
the equation should be corrected to fit the data of the problem. With the corrected equation a mass of 0.5 grams remains after 150 years
Step-by-step explanation:
for the mass y( in grams)
y=23* (1/2)^(t/45), t ≥ 0.
the initial mass is at t=0 , then
y= 23 grams → should be 16 grams
half-life from the equation = 45 years → should be 30 years
the correct equation should be
y=16*(1/2)^(t/30), t ≥ 0
then after 150 years → t= 150
y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams
then a mass of 0.5 grams remains after 150 years
(x-2)(x+2) is factorize is given eq
Answer:
Since the square root of 25 = 5 and the square root of 36 is 6 it is known that the square root of 33 is between 5 and 6.
Step-by-step explanation:
The key to this is to think about perfect squares, specifically the ones closest to 33. These are 25 and 36, which have square roots of 5 and 6 respectively. Because 33 is between these numbers, you know for certain that its square root is between <em>their</em> square roots too.
Let me know if you need a more in-depth explanation!