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3 years ago

(Notimated as brainliest 25 points )

Mathematics

1 answer:

Genrish500 [490]3 years ago

7 0

Answer:

Triangle ABC is not a right triangle because d) it doesn't have a pair of perpendicular sides

Step-by-step explanation:

Perpendicular sides mean that the slopes are "opposite reciprocals" of each other.

Example: slope is 1/2 and the perpendicular line's slope is -2

How? 1/2 changes to 2 (you flip it, reciprocal), and then from 2 to -2 (apply opposite sign)

So when you calculate the slopes of AB, AC, and BC, none of their slopes are opposite reciprocals of each other. You can calculate the slopes of each and compare them if you want to check.

I really hope this helps, do you think you can tell me if you got the answer correct? I'd feel really bad if you got it wrong because of me. All I know is that it's not a right triangle.

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3 years ago

Find the x-intercept for 11x - 33y = 99

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3 years ago

A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is

Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

$\Delta s = s_2-s_1$

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

$\Delta x = x_2-x_1$

So we can use the given points $P1:(x_1,y_2) \text{ and } P_2: (x_2,y_2)$ on the displacement formula

$\Delta x = 15-4\\\Delta x = 11$

In the same manner we can look at the y components of those points to find the vertical displacement

$\Delta y = 17-8\\\Delta y =9$

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

$\tan(\theta) = \cfrac{\Delta y}{\Delta x}$

Solving for the angle we get

$\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)$

Replacing values

$\theta = \tan^{-1}\left(\cfrac{9}{11}\right)$

Which give us

$\theta = 39.3^\circ$

So the projection angle is 39.3 degrees.

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3 years ago

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S_A_V [24]

Because HI and JK are parallel, that makes their angles congruent. So angle K equals angle I
So the interior angles of a triangle add up to 180°
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116°+x°=180°
X=180-116
X=64°

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3 years ago