Answer:
Versatility
Explanation:
The capacity of computer of performing more than one task at the same time is called versatility of computer. Versatility means the capacity to perform different types of work completely
Answer:
Explanation:
From the given information;
We will like you to understand that the source port numbers and destination port number can be any number. For that reason, the ones being used here will just be examples.
NOTE:
That the destination port numbers sent from A to S and B to S are the same in their segments.
That the destination port numbers sent from S to A and S to B are the same in their segments.
From A to S, the segment sent possibly could have the source port number 467 and destination port number as 23(Telnet)
From B to S, the segment sent possibly could have the source port number 513 and destination port number as 23(Telnet).
From S to A, the segment sent possibly could have the source port number as 23(Telnet) and destination port number as 467.
From S to B, the segment sent possibly could have the source port number as 23(Telnet) and destination port number as 513.
Yes, it is possible. This is because the inclusion of IP in the segments is to recognize the host.
No, the source ports will be different. Because source port number from A to S can't be the same from B to S at the time they are in the same host.
Answer:
Metrical task system algorithm is the online algorithm that is used for organizing the online problems like k-server issues, paging issues etc.This task system works in the form of metrics to decrease the complete cost experienced due to processing of the operation and analyzing the competition.
It can be used for the online shopping project for the analyzing the comparison between the performance on basis of online and offline trends and then optimization can take place according to the the results.
Answer:
negatives = []
zeros = []
positives = []
while True:
number = input("Enter a number: ")
if number == "":
break
else:
number = int(number)
if number < 0:
negatives.append(number)
elif number == 0:
zeros.append(number)
else:
positives.append(number)
for n in negatives:
print(n)
for z in zeros:
print(z)
for p in positives:
print(p)
Explanation:
Initialize three lists to hold the numbers
Create a while loop that iterates until the user enters a blank line
Inside the loop:
If the number is smaller than 0, put it in the negatives list
If the number is 0, put it in the zeros list
Otherwise, put the number in the negatives list
When the while loop is done, create three for loops to print the numbers inside the lists
Answer:
b. The names in the list should be in alphabetical order.
Explanation:
A binary search is an algorithm used for searching for an item in a list or array. The algorithm first sorts the data structure into order and then divides it into halves. If the searched item is less than the middle item in the list, then the algorithm searches for the target in the first half, else, in the second half. This reduces the time complexity of the search.
