Ask question

Ask question

All categories

2 years ago

8

What is quadrilateral ABCD is translated A.7 units left and 4 units up B.6 units right and 4 units down C.7 units right and 4 un

its down D.6 units right and 5 units down .

1 answer:

Vera_Pavlovna [14]2 years ago

3 0

It states in the problem the coordinates only in word form.
A. (-7,4)
B. (6,-4)
C. (7,-4)
D. (6,-5)

You might be interested in

What is the equation of the line whose slope is 1/3 and y-intercept is -4?

faltersainse [42]

Answer:

y=1/3x-4

Step-by-step explanation:

the slope-intercept format of the line is y=mx+b, where m is the slope and b is the y intercept.

we are given the slope (1/3) and the y intercpet (-4).

substitute the numbers into the equation

y=1/3x-4

the answer is y=1/3x-4

hope this helps!

3 0

2 years ago

John runs 15 miles in 3 hours. How many miles can John run per hour?

tekilochka [14]

He can run 5 miles per hour

6 0

3 years ago

Read 2 more answers

Need some help with this question in the image<br><br>Cheers

iren [92.7K]

Step-by-step explanation:

a) 24.7×52.3=1291.81

On rounding off to 3 significant digits we get

1290

b)

$\sqrt{ {42}^{2} - {28}^{2} }$

$\sqrt{1764 -784 } = \sqrt{980}$

=31.304951

On rounding off to 5 significant figures we get

=31.305

c)

$\sqrt[3]{78} = 4.27265$

On rounding off to 2 significant figures we get

=4.3

Hence required answers

a)1290

b)31.305

c)4.3

I hope it helped you

5 0

1 year ago

How are each term related to one another in the sequence 2,90,4,87,6,12,8,51,10 ?

Setler [38]

Every other number from the first, 3rd, 5th, ..etc it adds 2 for the next number.
For the 2nd, 4th, 6th, etc term, its supposed to be 90, 78, 65, 51?
If so, It started with -12 then -13 after that -14 find the next term, all you need to do is to -15 to the current number, which is 51. then you get 36

5 0

3 years ago

CON PROCESOS POR FAVOR

labwork [276]

Answer:

$\dfrac{149}{40}$

$\dfrac{38}{15}$

Step-by-step explanation:

$(\dfrac{7}{8} + \dfrac{4}{5}) - (\dfrac{9}{20} + \dfrac{-5}{2}) =$

$= (\dfrac{7}{8} \times \dfrac{5}{5} + \dfrac{4}{5} \times \dfrac{8}{8}) - (\dfrac{9}{20} + \dfrac{-5}{2} \times \dfrac{10}{10})$

$= (\dfrac{35}{40} + \dfrac{32}{40}) - (\dfrac{9}{20} + \dfrac{-50}{20})$

$= \dfrac{67}{40} - (-\dfrac{41}{20})$

$= \dfrac{67}{40} + \dfrac{41}{20} \times \dfrac{2}{2}$

$= \dfrac{67}{40} + \dfrac{82}{40}$

$= \dfrac{149}{40}$

$(-\dfrac{6}{4} + \dfrac{3}{2}) + (\dfrac{6}{5} + \dfrac{4}{3}) =$

$= (-\dfrac{3}{2} + \dfrac{3}{2})+ (\dfrac{6}{5} \times \dfrac{3}{3} + \dfrac{4}{3} \times \dfrac{5}{5})$

$= 0 + \dfrac{18}{15} + \dfrac{20}{15}$

$= \dfrac{38}{15}$

4 0

1 year ago