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grin007 [14]
4 years ago
6

Select the correct answer from the drop-down menu.

Mathematics
1 answer:
inessss [21]4 years ago
6 0

Answer:

<h2>D.</h2>

Step-by-step explanation:

The choices to this question are

a.) 1/tan(90-A)

b.) 1/sin A

c.) 1/cos(90-A)

d.) 1/tan A

We know that

tanx=\frac{sinx}{cosx}, which is a trigonometric identity.

If tan(90-A) then,

tan(90-A)=\frac{sin(90-A)}{cos(90-A)}

But, sin (90-A)=cosA and cos(90-A)=sinA

So,

tan(90-A)=\frac{cosA}{sinA}

Which is the inverse of tangent, so

tan(90-A)=\frac{1}{tanA}

Therefore, the right answer is D.

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Yes it is ...........
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Read 2 more answers
Select all correct statements from the relation shown on the graph below.
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<h3>Answer:</h3>

after watching a two minute video on how to tell if a relation is a function, I can confidently tell you that the answers are 2, 3, & 4.

<h3>step-by-step explanation</h3><h3></h3>

answers 3 & 4 are the x and y coordinates of the points.

this relation is not a function because it does not pass the vertical line test.

( the vertical line test is where you look at all the vertical lines on the page and check if any of them have multiple dots on them. in this case, the line at x coordinate 1 has dots on both (1, 1) and (1, -1) )

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4 years ago
Walmart sells to sizes of milk. One contains a half gallon of milk and costs $1.82.
aivan3 [116]

Answer:

Difference = $0.01

Step-by-step explanation:

Given that:

Cost of half gallon = $1.82

Cost of one gallon = $3.68

First we will convert gallons to ounces.

1 gallon = 128 ounces

half gallon = 64 ounces

Now,

we will find unit rate of both.

Unit rate of half gallon = \frac{1.28}{64} = \$0.02

Unit rate of one gallon = \frac{3.68}{128} = \$0.03

Difference= 0.03 - 0.02 = $0.01

Hence,

Difference = $0.01

5 0
3 years ago
Cameron can read 196 words in a minute. Robert reads 1.6 times as fast. How many words can Robert read in a minute?
Naddik [55]
Robert can read 313.6 (rounded = 314)words per minute. 
6 0
3 years ago
Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c
Elina [12.6K]

Answer:

t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058

The degrees of freedom are:

df=8+9-2=15

And the p value would be:

p_v =P(t_{15}>2.058) =0.0287

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are significantly higher than those in Dallas

Step-by-step explanation:

Data given

n_1 =8 represent the sample size for group Boston

n_2 =9 represent the sample size for group Dallas

\bar X_1 =47 represent the sample mean for the group Boston

\bar X_2 =44 represent the sample mean for the group Dallas

s_1=3 represent the sample standard deviation for group Boston

s_2=3 represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

\sigma^2_1 =\sigma^2_2 =\sigma^2

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

The statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t student distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

Replacing we got:

\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9

And the deviation would be just the square root of the variance:

S_p=3

The statitsic would be:

t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058

The degrees of freedom are:

df=8+9-2=15

And the p value would be:

p_v =P(t_{15}>2.058) =0.0287

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are significantly higher than those in Dallas

5 0
4 years ago
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