20/21 is the answer to your problem.
If there are 272.5 rotations in a mile, and 5280 ft in a mile, then there are 5280 ft in 272.5 rotations. Divide 5280 by 272.5 gives us 19.4 ft/rotation.
That's the circumference of the wheel, and since c = πd, 19.4/π = d, d = 6.2 ft. The diameter of the wheel is how tall it is.
Does this help? Any questions?
Answer: ↓↓↓
Step-by-step explanation:
1. EF || HG, HE || FG
2. Reflexive Property
3. Alternate Interior Angles
4. SAS
Answer:
a. 60
b. -32
c. 3598
d. -6
Step-by-step explanation:
all you have to do is plug in the numbers that are given to you for the missing variables and then solve it regularly.
6×7+2×3
5×(-18)÷3-2
(6×10)^2-10÷5
(1-3)(1+2)
