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4 years ago

Please check my answer!

Mathematics

2 answers:

Ugo [173]4 years ago

3 0

Equation 1 = 4.12
Equation 2 = 5.099
Equation 3 = 4
Equation 4 = 3

I think the answer is B.

natita [175]4 years ago

3 0

The answer is B. The value of x would be just over 5.

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If the opposite of g(x) is –g(x), then –g(x) =

ale4655 [162]

-g(x) = g(x) this statement is true because of the commutative property

hope this helps

6 0

3 years ago

Read 2 more answers

Plz help i really do need help

Maslowich

Answer:

it just says PDF won't let me download I. sorry

6 0

4 years ago

g A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estim

kipiarov [429]

Answer:

a) n= 1045 computers

b) n= 442 computers

c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.

Step-by-step explanation:

Hello!

The variable of interest is

X: Number of computers that use the new operating system.

You need to find the best sample size to take so that the proportion of computers that use the new operating system can be estimated with a 99% CI and a margin of error no greater than 4%.

The confidence interval for the population proportion is:

p' ± $Z_{1-\alpha /2}$ * $\sqrt{\frac{p'(1-p')}{n} }$

$Z_{1-\alpha /2}= Z_{0.995}= 2.586$

a) In this item there is no known value for the sample proportion (p') when something like this happens, you have to assume the "worst-case scenario" that is, that the proportion of success and failure of the trial are the same, i.e. p'=q'=0.5

The margin of error of the interval is:

d= $Z_{1-\alpha /2}$ * $\sqrt{\frac{p'(1-p')}{n} }$

$\frac{d}{Z_{1-\alpha /2}} = \sqrt{\frac{p'(1-p)}{n} }$

$(\frac{d}{Z_{1-\alpha /2}})^2 = \frac{p'(1-p')}{n}$

$n * (\frac{d}{Z_{1-\alpha /2}})^2 = p'(1-p')$

$n= [p'(1-p')]*(\frac{Z_{1-\alpha /2}}{d} )^2$

$n=[0.5(1-0.5)]*(\frac{2.586}{0.04} )^2= 1044.9056$

n= 1045 computers

b) This time there is a known value for the sample proportion: p'= 0.88, using the same confidence level and required margin of error:

$n= [p'(1-p')]*(\frac{Z_{1-\alpha /2}}{d} )^2$

$n= [0.88*0.12]*(\frac{{2.586}}{0.04})^2= 441.3681$

n= 442 computers

c) The additional information in part b affected the required sample size, it was drastically decreased in comparison with the sample size calculated in a).

I hope it helps!

4 0

4 years ago

Luba walked 5 miles in 1 1/2 hours. How fast did she walk in miles per hour?

lakkis [162]

Answer:

c or d sorry if I'm wrong

Step-by-step explanation:

I think it's your d because of the shortest answers and they're the only two that makes sense

8 0

3 years ago

870.497 ÷ 0.823=?<br> round your answer to the nearest whole number

jarptica [38.1K]

Answer:

870.497 ÷ 0.823=1.057 so to the nearest whole number it would be 1

Step-by-step explanation:

cause 0-4 numbers are rounded down

5 0

3 years ago

Read 2 more answers