Looking at the equation, you could see that it is in vertex form. Vertex form looks like this: y=a(x-h)^2+k where a is the slope to find the first point away from the origin and (h,k) is the vertex. So, the vertex is (3,-1). The first point away from the origin is up two, over one, so the slope is 2. This means that a is 2. One way you could check this is by putting 2 in for a. If you put it into standard form, it would be 2x^2-12x+17. To find the x in the vertex when the equation is in standard form we use -b/2a. So it would give us 3 for x. If we put in 3 for x, we get -1 for y, so the vertex is (3,-1). This means that a is 2. Sorry for this lengthy answer, hope it helps.
Answer:A. -1.11x^2+ 3.74+ 10.64
Step-by-step explanation:
a. p. e. x. (just took the test)
First, I'm going to separate factor the expression inside of the square root.
sqrt[ (2/18) * (x^5) ]
sqrt[ (1/9) * (x^5) ]
We can take the square root of 1/9 easily, because 1 and 9 are both perfect squares. The square root of 1/9 is 1/3.
Looking at the x^5, we can separate it into x^2 * x^2 * x^1. The square root of x^2 is x. So, we now also have an x^2 on the outside because there are two x^2s in our expanded form.
ANSWER: (x^2 * sqrt(x)) / 3
(Option 1)
Hope this helps!
Answer:
Step-by-step explanation:
10+6n=n-5
6n-n=-5-10
5n=-15
n=-3
