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kari74 [83]
3 years ago
7

Please help worth 30 pts​

Mathematics
2 answers:
cestrela7 [59]3 years ago
5 0

Answer:

So I believe your just graphing here like a line or bar graph. Look at images in Google for references if needed.

Elanso [62]3 years ago
4 0

Answer: ok so you need to first draw a shape

Δ

a triangle right

so the only time its is in motion is when its a sign at the road for directions

it nevers accelerates

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Write a system of linear inequalities represented by the graph.​
mestny [16]

Answer:

Alright so youd havee to right the terms in order which should be easy then your done! Hope this helped!

Step-by-step explanation:

8 0
2 years ago
Triangles are similar. Round answer to nearest tenth (step by step)
ozzi

Answer:

13.5

Step-by-step explanation:

Similar = alike but not the same

A lot of times in geometry it would mean that they have the same shape, just different size, so first find the ratio:

6/12 = 1/2

27 * 1/2 = 27/2 = 13.5

7 0
2 years ago
Read 2 more answers
Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}  (1)

furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

I_n=\int_0^{\infty}x^ne^{-ax^2}dx

furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

5 0
2 years ago
Read 2 more answers
What is the answer to the problem
vovikov84 [41]

Answer: 6

Step-by-step explanation: DE is 4+2 so EF would be the same if it is equal.

3 0
3 years ago
Find the length of side X
NISA [10]

Answer:

C

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the 2 other sides, that is

x² + 6² = 17²

x² + 36 = 289 ( subtract 36 from both sides )

x² = 253 ( take the square root of both sides )

x = \sqrt{253} → C

7 0
2 years ago
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