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3 years ago

10

200 students, which was 40% of the 7th graders said that the dress code was an important issue at school. How many students are

in the 7th grade?

1 answer:

xeze [42]3 years ago

8 0

Answer:

there are 80 students

Step-by-step explanation:

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Jaden is flying a kite with an angle of elevation of 33 degrees. If Jaden lets out 275 feet of string, how high above the ground

pshichka [43]

Answer:

149.8 feet

Step-by-step explanation:

θ = Angle of elevation = 33°

The length of string Jaden lets out = Hypotenuse = 275 feet.

How high above the ground that the kite is flying = Opposite Side.

We are solving this question using the Trigonometric function of Sine

Sin θ = Opposite Side/Hypotenuse

Sin 33 = Opposite/275 feet

Cross Multiply

Sin 33 × 275 feet = Opposite

Opposite side(Height ) = 149.77573463 feet

Approximately to the nearest tenth = 149.8 feet

8 0

3 years ago

If f(x) = 2(x)^2 + 5 square root (x+2), complete the following statement (round your answer to the nearest hundredth): f(2) =

mojhsa [17]

$f(x) = 2(x)^{2} +5 \sqrt{x+2}$

$f(2) = 2(2)^{2} + 5 \sqrt{(2)+2}$

$f(2) = 2(4) + 5\sqrt{4}$

$f(2) = 8 + 5(2)$

$f(2)= 8+10$

f(2) = 18

3 0

3 years ago

In detail explain how to multiply in binomial of (5x-7 (2x-1) in foil method

Nesterboy [21]

Step-by-step explanation:

First

Outer

Inner

Last

First- 5x*2x=10x^2

Outer-5x*-1= -5x

Inner--7*2x= -14x

Last- -7*-1= 7

10x^2-5x-14x+7

you can simplify it further however thats the answer

4 0

3 years ago

Arrange the entries of matrix A in increasing order of their cofactors values

givi [52]

To find the cofactor of

$A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]$

We cross out the Row and columns of the respective entries and find the determinant of the remaining $2\times 2$ matrix with the alternating signs.

$Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|$

$Ac_{11}=4\times 1- -1\times 2$

$Ac_{11}=4+ 2$

$Ac_{11}=6$

$Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|$

$Ac_{12}=-(-7\times 1- -1\times -8)$

$Ac_{12}=-(-7- 8)$

$Ac_{12}=15$

$Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|$

$Ac_{21}=-(5\times 1- 3\times 2)$

$Ac_{21}=-(5-6)$

$Ac_{21}=1$

$A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|$

$Ac_{23}=-(7\times 2 -8\times 5)$

$Ac_{23}=-(14-40)$

$Ac_{23}=26$

$A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|$

$Ac_{31}=5\times -1 -4\times 3$

$Ac_{31}=-5-12$

$Ac_{31}=-17$

$A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|$

$Ac_{33}=7\times 4- -7\times 5$

$Ac_{33}=28+35$

$Ac_{33}=63$

Therefore in increasing order, we have;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

7 0

3 years ago

Read 2 more answers

Graph the function.<br> f(x)= 3/5x}=-5

Alinara [238K]

Start at negative 5 since that’s your y-intercept.
Since 3/5 is your slope and slope equals rise over run you go up 3 units and go right 5 units.

3 0

3 years ago