Log 2 over 3 = 0.10034333188
Answer:
W=1000C/tc
Step-by-step explanation:
First multiply both side 1000: 1000C=Wtc
Divide both side by tc: 1000C/tc=W (t, c ≠0)
Answer:
yes
Step-by-step explanation:
i cant see da pic
Answer:
0.40
Step-by-step explanation:
to find out the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8
Let A = sum of dice is 8
B = one lands in 5
P(B/A) = P(AB)/P(A) by conditional probability
P(AB) = sum is 8 and one is 5
So (5,3) or (3,5)
P(A) = sum is 8.
i.e. (2,6) (2,6) (3,5) (5,3) (4,4)
Required probability
= n(AB)/n(A)
=