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Galina-37 [17]
3 years ago
11

What is 17/3 in a percentage

Mathematics
1 answer:
Aneli [31]3 years ago
4 0
First, convert 17/3 to an improper fraction. 17/3 becomes 5 2/3.
Then convert 5 2/3 to a decimal.

5 2/3 becomes 5.666...

Then convert the decimal to a percent.

5.666... becomes approximately 566.66%
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Solve using substitution.<br><br> x = –2<br> 5x + 3y = 14
Nookie1986 [14]

Answer:  (-2, 8)

Explanation:

Plug x = -2 into the second equation. Isolate y.

5x+3y = 14

5(-2)+3y = 14

-10+3y = 14

3y = 14+10

3y = 24

y = 24/3

y = 8

We have x = -2 lead to y = 8.

Therefore, the ordered pair (x,y) = (-2,8) is the solution to this system.

4 0
2 years ago
Helpppppppppppppppppppppppp
Vaselesa [24]
The first thing to is factor the denominator of the rational function:
x^{2} -2x-3 to do this we'll need to find two number whose product is -3 and its sum is -2; those numbers are 1 and -3, so:
x^{2} -2x-3=(x+1)(x-3)
Now we can rewrite our rational function as follows:
f(x)= \frac{x-3}{(x+1)(x-3)}
Notice that we have a common factor (x-3) in both numerator and denominator; therefore we can cancel them:
f(x)= \frac{1}{x+1}

Taking all the above into consideration we realize that x=3 is a removable discontinuity; the correct answer is the first one: there is a hole in x=3 and asymptote  at x=-1.

4 0
2 years ago
At a competition with 7 runners, medals are awarded for first, second, and
il63 [147K]

Answer:

Option A - Permutation; number of ways = 210

Step-by-step explanation:

Given : At a competition with 7 runners, medals are awarded for first, second, and  third places. Each of the 3 medals is different.

To find : How many ways are there to  award the medals?        

Solution :

There are 7 runners but medals are three.

The first runner up got first medal as one is locked.

The second runner up got second medal as second is locked.

The third runner up got the third medal.

So, There is a permutation.

Number of ways to award the medals is ^7P_3

We know, ^nP_r=\frac{n!}{(n-r)!}

Substitute the values,

^7P_3=\frac{7!}{(7-3)!}

^7P_3=\frac{7\times 6\times 5\times 4!}{4!}

^7P_3=210

Therefore, Option A is correct.

Permutation; number of ways = 210

6 0
3 years ago
PLEASE HELP!!! THERE IS A PICTURE ATTACHED
telo118 [61]
Well, the problem is that he does not replace the first marble after he draws it. Therefore, yes, he has a 2/12 probability of drawing a yellow marble first, but then he has a 4/11 probability of drawing a red marble second, not 4/12. This is because there are going to only be 11 marbles left in the bag after he draws the first marble and does not replace it.

The correct answer would be:
(2/12)(4/11)=8/132=4/66=2/33
4 0
3 years ago
Read 2 more answers
Which diagram suggests a correct construction of a line parallel
ser-zykov [4K]
The third diagram is the correct answer.
8 0
3 years ago
Read 2 more answers
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