Answer:
8 days
Step-by-step explanation:
If the frog crawls up 4 feet and slips back 2 feet, then it will crawl...
4-2 = 2 ft each day
Let x be the amount of days it'll take for the frog to reach the top of the well given he crawls 2 feet each day:
2x=18
Divide both sides by 2
x=9
But, at 7 days, the frog will already have crawled 14 feet. This means that on the 8th day, the frog will crawl 4 feet and reach the top of the well before he slips back down. Therefore the answer is 8 days
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Answer:
y = -5x + 7
Step-by-step explanation:
Segment bisector of the segments AB and CD will pass through the midpoint of these segments.
Midpoint of a segment is given by the coordinates =
where, and are the coordinates of the extreme ends of the segments.
Coordinates of the midpoint of AB =
= (1, 2)
Coordinates of the midpoint of CD =
= (2, -3)
Let the equation of the line will be,
Slope of the line passing through two points and is,
m =
=
= -5
Therefore, equation of the line will be passing through (1, 2) and slope (-5),
y - 2 = (-5)(x - 1)
y = -5x + 5 + 2
y = -5x + 7
The time it will take the pebble to reach the maximum height is 1.5secs
Given the quadratic equation that models the path of the pebble expressed as p(t) = –16t^2 + 48t + 110
We can calculate the time taken by the pebble to reach the maximum height.
At maximum height, the velocity of the pebble is zero i.e. p'(t) = 0
p'(t) = -32t + 48
0 = -32t + 48
32t = 48
t = 48/32
t = 1.5secs
Hence the time it will take the pebble to reach the maximum height is 1.5secs
Learn more on velocity function here:brainly.com/question/25749514