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coldgirl [10]
3 years ago
12

the amount of military spending M (in billions of dollars) in the U.S. during year t is given approximately by the equation M=48

.81t+304.30 where t=0 corresponds to the year 2000. During what year did the military spending in the U.S. hit apporximately $694.78 billion?
Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

2008

Step-by-step explanation:

M = 48.81t + 304.30

M = 694.78                            Solve for t

694.78 = 48.81t + 304.30     Subtract 304.30 from each side

390.48 = 48.81t                    Divide each side by 48.81

t = 390.48/48.81  

t = 8.00 yr

=====

Year = 2000 + t

Year = 2000 + 8.00

Year = 2008

Military spending hit $694.78 billion at the end of 2008.

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The figure show the dimensions of a city park in feet.
Soloha48 [4]

Answer:

73,084

Step-by-step explanation:

3 0
3 years ago
Why is -a² is always negative (a ≠ 0) and why is (-a)² is always positive?
hjlf
-a^2=(-1)\cdot a\cdot a

Regardless of the sign of a, we have a\cdot a=a^2\ge0 (never negative). But multiplying by -1 makes it negative.

On the other hand,

(-a)^2=((-1)\cdot a)^2=(-1)^2\cdot a^2=1\cdot a^2=a^2

which can never be negative for real a.
6 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by
a_sh-v [17]

Answer:

Dimension of the box is 16.1\times 7.1\times 2.45

The volume of the box is 280.05 in³.

Step-by-step explanation:          

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is L=21-2h

The width of the box is W=12-2h

The volume of the box is V=L\times W\times H

V=(21-2h)\times (12-2h)\times h

V=(21-2h)\times (12h-2h^2)

V=252h-42h^2-24h^2+4h^3

V=4h^3-66h^2+252h

To maximize the volume we find derivative of volume and put it to zero.

V'=12h^2-132h+252

0=12h^2-132h+252

Solving by quadratic formula,

h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}

h=\frac{132\pm72.99}{24}

h=2.45,8.54

Now, substitute the value of h in the volume,

V=4h^3-66h^2+252h

When, h=2.45

V=4(2.45)^3-66(2.45)^2+252(2.45)

V\approx 280.05

When, h=8.54

V=4(8.54)^3-66(8.54)^2+252(8.54)

V\approx -170.06

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is L=21-2(2.45)=16.1

The width of the box is W=12-2(2.45)=7.1

So, Dimension of the box is 16.1\times 7.1\times 2.45

6 0
3 years ago
Complete the table to show the total distance walked in each case. Please use decimal notation for your answer.
Alex17521 [72]

Answer:

its i dont know

Step-by-step explanation:

7 0
3 years ago
What is the value of x?<br> (9x - 3)<br> (6x)<br> 48°<br> Enter your answer in the box.<br> X=
Dima020 [189]

Answer:  x = 9

Step-by-step explanation:

The sum of three interior angles of a triangle is 180°.

(9x - 3)  + (6x)  + 48° = 180°

9x - 3 + 6x + 48 = 180

15x + 45 = 180

15x = 135

x = 9

6 0
3 years ago
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