Which set of line segments can be used to construct a triangle?

If f(x)=2x-7, then find f(8)

Artyom0805 [142]

It should be 9. I hope this helps. If it's not 9 then can u please give me a list of your answers to choose from.

5 0

4 years ago

Solving fp Algebra 2 I do not understand how to solve this, could someone please explain?

Olenka [21]

$f(x) = \sqrt{x + 2}$
What's The Fixed Point? Well, Let's Assume X=0, this is our point.

$f(0) = \sqrt{0 + 2} \\ f(0) = \sqrt{2} \\ this \: is \: our \: fixed \: point \: \\ (0, \sqrt{2} )$
OR

$f(p) = \sqrt{p + 2} \\ \\ or \: \sqrt{x + 2} = 0 \\ ( \sqrt{x + 2} ) ^{2} = {0}^{2} \\ x + 2 = 0 \\ x = - 2$
I'm unaware of the nature of the question, so here are some different ways a fixed point is found based on the merits of the question.

4 0

3 years ago

Order these numbers from least to greatest.

PSYCHO15rus [73]

<h3>Answer: 3.1691, 5.8, 5.802, 5.82</h3>

Explanation:

The smallest item is 3.1691 which is listed first. This is because 3 is smaller than 5.

Now to sort the values that start with 5.

Think of 5.82 as 5.820; think of 5.8 as 5.800

We can see that 820 is larger than 800, which means 5.820 is larger than 5.800; in short, 5.82 > 5.8

Through similar logic, we can see that 5.82 > 5.802 and it further means 5.82 is the largest item. The next largest is 5.802

The sub-list {5.802, 5.82, 5.8} sorts to {5.8, 5.802, 5.82}. These values are then written after the 3.1691 mentioned. This will produce the fully sorted list from smallest to largest.

4 0

3 years ago

Kaira's gross pay is $4,633. Her deductions total $1,009.13. What percent of hergross pay is take-home pay?Round to the nearest

Delvig [45]

Answer:

$\text{ 78\%}$

Explanation:

Here, we want to get the percentage of the gross pay is the take-home pay

Mathematically, we have to divide the take-home pay by the gross pay and multiply it by 100%

Her take-home pay is the difference between her gross pay and her deductions

We have this as:

$\text{ 4633 - 1009.13 = \$3,623.87}$

We have this as:

$\frac{3623.87}{4633}\text{ }\times\text{ 100 \% = 78\%}$

7 0

1 year ago

A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature

Westkost [7]

Answer:

(a) The value of k is $\frac{1}{15}$ .

(b) The probability that at most three forms are required is 0.40.

(c) The probability that between two and four forms (inclusive) are required is 0.60.

(d) $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

Step-by-step explanation:

The random variable Y is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

$P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right$

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of k.

$\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}$

Thus, the value of k is $\frac{1}{15}$ .

(b)

Compute the value of P (Y ≤ 3) as follows:

$P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40$

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

$P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\ =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60$

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ to be the pmf of Y it has to satisfy the conditions:

$P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\$
$\sum P(y)=1$

Check condition 1:

$y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0$

Condition 1 is fulfilled.

Check condition 2:

$\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1$

Condition 2 is not satisfied.

Thus, $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

7 0

3 years ago