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3 years ago

Solve the following equation. Then place the correct number in the box provided.

Mathematics

2 answers:

LuckyWell [14K]3 years ago

7 0

×+6-5=8-2
x+1=6
-1 -1
----------
x=5

shtirl [24]3 years ago

7 0

Answer:

Step-by-step explanation:

x + 6 - 5 = 8 - 2

8-2= 6.

6-5= 1.

So we can say x+1=6

So x = 5

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En una competición participan 200 atletas, 2/5 son españoles, 1/3 del resto son franceses, 35 son alemanes y el resto son ingles

Bas_tet [7]

Answer:

7/40

Step-by-step explanation:

La fraccion de Alemanes son 35/200=7/40

6 0

3 years ago

9 + x - 3 = 4x - 3 <br><br> Find x, please explain asap

Vesnalui [34]

Answer:

x = 3

Explanation:

To simplify this equation, don't worry about the -3, since there is one on both sides. Therefore, they cancel out.

So, 9 + x = 4x

When you plug 3 in for x, it becomes:

9 + 3 = 4 x 3

12 = 12

This equation is true, therefore, x is your answer!

5 0

2 years ago

The mean cost of domestic airfares in the United States rose to an all-time high of $385 per ticket (Bureau of Transportation St

saveliy_v [14]

Answer:

a)0.067

b)0.111

c)0.612

d)$687.28

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $385

Standard Deviation, σ = $110

We are given that the distribution of domestic airfares is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(domestic airfare is $550 or more)

P(x > 550)

$P( x > 550) = P( z > \displaystyle\frac{550 - 385}{110}) = P(z > 1.5)$

$= 1 - P(z \leq 1.5)$

Calculation the value from standard normal z table, we have,

$P(x > 550) = 1 - 0.933 = 0.067= 6.7\%$

b) P(domestic airfare is $250 or less)

$P(x \leq 250) = P(z \leq \displaystyle\frac{250-385}{110}) = P(z \leq -1.22)$

Calculating the value from the standard normal table we have,

$P( x \leq 250) = 0.111 = 11.1\%$

c))P(domestic airfare is between $300 and $500)

$P(300 \leq x \leq 500) = P(\displaystyle\frac{300 - 385}{110} \leq z \leq \displaystyle\frac{500-385}{110}) = P(-0.77 \leq z \leq 1.04)\\\\= P(z \leq 1.04) - P(z < -0.77)\\= 0.851 - 0.239 = 0.612 = 61.2\%$

$P(300 \leq x \leq 500) = 61.2\%$

d) P(X=x) = 0.03

We have to find the value of x such that the probability is 0.03.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 385}{110})=0.03$

$= 1 -P( z \leq \displaystyle\frac{x - 385}{110})=0.03$

$=P( z \leq \displaystyle\frac{x - 385}{110})=0.997$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 385}{110} = 2.748\\x = 687.28$

Hence, the domestic fares must be $687.28 or greater for them to lie in the highest 3%.

7 0

3 years ago

Please help! What is the function for the graph

Evgen [1.6K]

When x = 0 the value of the function is 2 so its either A or B.

When x = 1, y = 8 so substituting these values in A we get:-

8 = 2 * 8^1 = 16 so

its Not A. Try B:-

8 = 2 *4^1 = 8 which fits

Answer is choice B

7 0

3 years ago

Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,

Aleksandr-060686 [28]

Answer:

The expected value of the points earned on a single roll in this game is $\dfrac{1}{6} = 0.1667$ .

Step-by-step explanation:

We are given that consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number, that many points will be added to the player’s total. Any other roll will be deducted from the player’s total.

Assuming that the numbered cube is a dice with numbers (1, 2, 3, 4, 5, and 6).

Here, the prime numbers are = 1, 2, 3 and 5

Numbers which are not prime = 4 and 6

This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

Here, we have to make a probability distribution to find the expected value of the points earned on a single roll in this game.

Note that the probability of getting any of the specific number on the dice is $\dfrac{1}{6}$ .

Numbers on the dice (X) P(X)

+1 $\frac{1}{6}$

+2 $\frac{1}{6}$

+3 $\frac{1}{6}$

-4 $\frac{1}{6}$

+5 $\frac{1}{6}$

-6 $\frac{1}{6}$

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

Now, the expected value of X, E(X) = $\sum X \times P(X)$

= $(+1) \times \frac{1}{6} +(+2) \times \frac{1}{6} +(+3) \times \frac{1}{6} +(-4) \times \frac{1}{6} +(+5) \times \frac{1}{6} +(-6) \times \frac{1}{6}$

= $\frac{1}{6} + \frac{2}{6} + \frac{3}{6} - \frac{4}{6} + \frac{5}{6} - \frac{6}{6}$

= $\frac{1+2+3-4+5-6}{6}$

= $\frac{11-10}{6}= \frac{1}{6}$

Hence, the expected value of the points earned on a single roll in this game is $\frac{1}{6} = 0.1667$ .

4 0

3 years ago