1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
leva [86]
3 years ago
8

Graph y=(x-2)^2-16 . Please help?!

Mathematics
2 answers:
insens350 [35]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Sauron [17]3 years ago
4 0

Answer:

graph c is the correct answer


You might be interested in
Simplyfly (-56) divided bye 7
MakcuM [25]

Answer: -8

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is x? (X,4) and (-7,-6); slope: 5/7
Ghella [55]

Answer:

Step-by-step explanation:

-6-4=-10

-7-x

x=7

<u>-10</u>

-14    is equal to 5/7

4 0
3 years ago
Select all that apply.
julsineya [31]

Answer:

The first and third is correct.

Step-by-step explanation:

I'm not a expert but I know its right.

6 0
3 years ago
Read 2 more answers
What is the result of substituting for y in the bottom equation<br> y=x+3<br> y=x^2+2x-4
8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

<em><u>Solution:</u></em>

Given that,

y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4  ----- eqn 2

<em><u>We have to substitute eqn 1 in eqn 2</u></em>

x + 3 = x^2 + 2x - 4

\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0

\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}

x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}

x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925

Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

6 0
3 years ago
Evaluate. –1.65 + (–3.4)
elena55 [62]
Hey there! 

This seems like a algebraic expression

SO,
Remember: negative and negative = positive
                      positive and positive = positive
                     positive and negative = negative
                       negative and positive = negative

In this problem we will be doing negative and negative so that means our answer will be a negative 

Firstly, lets line up our decimals to solve this problem (once when you do that , you can solve it easier)

-1.65 &#10;\\ +&#10;\\ (-3.4)&#10;

Answer: 
-5.05

Good luck on your assignment and enjoy your day

~LoveYourselfFirst:)
6 0
3 years ago
Other questions:
  • A circular picture is 8 inches in diameter.
    15·1 answer
  • When p = 12, t = 2, and s = 1/6 , r = 18. If r varies directly with p and inversely with the product of s and t, what is the con
    13·2 answers
  • sarah plans to buy a car in five years, so she invests $10,000. she receives an annual interest rate of 5%, compounded semiannua
    11·1 answer
  • Please answer question 10
    14·1 answer
  • A set of n = 5 pairs of x and y values has ssx = 10, ssy = 40 and sp = 10. for these data, the pearson correlation is
    8·1 answer
  • Where do you use percents in everyday life?​
    6·1 answer
  • Penny reads 11 pages in one fourth hour. What is the unit rate for pages per​ hour? For hours per​ page?
    11·2 answers
  • A wheel rolling at a constant speed has a radius of 15 inches and takes 30
    15·1 answer
  • Which shows how to correctly solve for C2, the circumference of any circle with radius r? Because StartFraction pi Over 1 EndFra
    11·2 answers
  • Plzzzzzzzzzz<br> help plzzzzzz
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!