A 2600-pound truck is stopped at a red light on a hill with an incline of 25°. Ignoring the force of friction, what force is req
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The values are 5i, -4, 2√2i, -16, -50i and i.
<h3>What is an imaginary number?</h3>An imaginary number is a number that, when squared, has a negative result, and is defined by its property i² = −1 or i = √-1.
Given are numbers,
1) √-25 = √25*√-1 = 5i
2) √-2√-2 = 2i*2i = 4i² = -4
3) √-8 = √8*√-1 = 2√2i
4) (4i)² = 16*i² = -16
5) (2i)(5i)² = 2i*25i² = 50i³ = -50i
6) i²*i³* = -1*(-i)*1 = i
Hence, The values are 5i, -4, 2√2i, -16, -50i and i.
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Answer:
Real values of x where x < -1
Step-by-step explanation:
Above the x-axis, the function is positive.
The function is decreasing when the gradient is negative.
The function has a positive
coefficient, therefore the vertex is a local minimum;
This means the gradients are negative before the vertex and positive after it;
To meet the conditions therefore, the function must be before the vertex and above the x-axis;
This will be anywhere before the x-intercept at x = -1;
Hence it is when x < -1.