Step-by-step explanation:
50% interest annually.
that means he gets 50% interest of the invested capital every year.
and that means he gets 50% of $70 in one year.
70 = 100%
1% = 100%/100 = 70/100 = $0.70
50% = 1%×50 = 0.7 × 50 = $35
he will earn $35 interest in one year.
as you noticed: 50% simply means 1/2 (as 100% stands for the whole).
There are 12 inches in a foot, so 9ft = 108in. Also, 80% = 0.8. Therefore the formula is:
h(n) = 108 * 0.8^n.
To find the bounce height after 10 bounces, substitute n=10 into the equation:
h(n) = 108 * 0.8^10 = 11.60in (2.d.p.).
Finally to find how many bounces happen before the height is less than one inch, substitute h(n) = 1, then rearrage with logarithms to solve for the power, x:
108 * 0.8^x = 1;
0.8^x = 1/108;
Ln(0.8^x) = ln(1/108);
xln(0.8) = ln(1\108);
x = ln(1/108) / ln(0.8) = -4.682 / -0.223 = 21 bounces
G(x)=− 4 x 2 +7g, left parenthesis, x, right parenthesis, equals, minus, start fraction, x, start superscript, 2, end superscr
steposvetlana [31]
For this case, what we should do is evaluate the function for different points within the range shown.
We then have the following table:
x g(x)
-2 -9
-1 3
0 7
1 3
2 -9
3 -29
4 -57
From where we observed that the average rate of change is:
-13
Answer:
the average rate of change of g over the interval [-2,4] is:
-13
Given:
The height h of an object after t seconds is
The height of a neighboring 50-foot tall building is modeled by the equation h=50.
The time (t) when the object will be at the same height as the building is found to be t = –2 and t = 5.
To find:
The statement which describes the validity of these solutions.
Solution:
We have,
Here, t is the time in seconds.
For t=-2,
For t=5,
So, the value of h is 50 at t=-2 and t=5.
We know that time is always positive so it cannot be negative value. It means t=-2 is not possible.
The solution t = 5 is the only valid solution to this system since time cannot be negative.
Therefore, the correct option is C.
