To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,
Therefore, 500 gallons of 80% antifreeze solution is required.
Answer:
- 12k² + kl
Step-by-step explanation:
Given
7kl - 3k(4k + 2l) ← distribute parenthesis by - 3
= 7kl - 12k² - 6kl ← collect like terms
= - 12k² + kl
Step-by-step explanation: To add and subtract fractions with the same denominator, or bottom number, place the 2 fractions side by side. Add or subtract the numerators, or the top numbers, and write the result in a new fraction on the top. The bottom number of the answer will be the same as the denominator of the original fractions.
Answer:
20
Step-by-step explanation:
a5
4*5
20
