Answer:
Step-by-step explanation:
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Answer:
Trapezoid 1 (left side):
Base 1 = 2
Base 2 = 5
Trapezoid 2 (right side):
Base 1 = 6
Base 2 = 8
Step-by-step explanation:
<u>1st trapezoid:</u>
b_1 = x
b_2 = x + 3
h = 4
Hence, area (from formula) would be:

<u>2nd trapezoid:</u>
b_1 = 3x
b_2 = 4x
h = 2
Putting into formula, we get:

Let's equate both equations for area and find x first:

We can plug in 2 into x and find length of each base of each trapezoid.
Trapezoid 1 (left side):
Base 1 = x = 2
Base 2 = x + 3 = 2 + 3 = 5
Trapezoid 2 (right side):
Base 1 = 3x = 3(2) = 6
Base 2 = 4x = 4(2) = 8
Answer:
The wall is 10.5 foot far from the bottom of the ladder.
Step-by-step explanation:
Given:
Height of the ladder leaning against wall (Hypotenuse) = 20 foot.
Height from where the window is above from the ground (Leg1) = 17 feet.
To find the distance of the bottom of the ladder far from the wall (Leg2) = ?
Now, by using the pythagorean theorem:





by squaring both sides

10.535 foot rounded nearest tenth is 10.5 foot.
Therefore, the wall is 10.5 foot far from the bottom of the ladder.
Answer:
y= -3/2x + 4
Step-by-step explanation:
hope this helps :)