Answer:
Correct option: second one
(Volume will be 9 times higher)
Step-by-step explanation:
The volume of a cylindrical can is given by the formula:
V = pi * r^2 * h
Where r is the base radius and h is the height.
If the new radius will be the triple of the old radius and the height will be the same, we have:
r' = 3r
h' = h
So, we can find the new volume V':
V' = pi * r'^2 * h'
V' = pi * (3r)^2 * h
V' = pi * 9r^2 * h = 9 * (pi * r^2 * h) = 9V
So we have that the new volume will be 9 times higher than the old volume.
Correct option: second one.
11.94 divided by 6 equals 1.99 so that would be $1.99. 8.12 divided by 4 equals 2.03 so that would be $2.03. So the box that has the lowest would be the box of 6 matches
Answers:
(a) BC = 40
(b) GF = 15
(c) CD = 45
(d) KM = 37.5
=========================================================
Explanations:
Part (a)
GF is a midsegment of triangle ABC, so GF is half that of the parallel base AC
AC = 30 so GF = (1/2)*AC = 0.5*30 = 15
--------------------------
Part (b)
For similar reasons as part (a), FB if half that of BC. This leads to FB = FC
FB = FC
FC = 20
since FB = 20
Now use the segment addition postulate
BC = BF + FC
BC = 20 + 20
BC = 40
Note: FB is the same as BF. The order of the letters does not matter.
--------------------------
Part (c)
GF = AD are the same length because of the single tickmark
GF = 15 so AD = 15
use the segment addition postulate
CD = CA + AD
CD = 30 + 15
CD = 45
--------------------------
Part (d)
EG = 15 since GF = 15 (and EG = GF by the single tickmark)
use the segment addition postulate
EF = EG + GF
EF = 15 + 15
EF = 30
The length of KM is the average of the base lengths EF and DC, since KM is a midsegment of the trapezoid
KM = (EF+DC)/2
KM = (30+45)/2
KM = (75)/2
KM = 37.5
You have problem which looks like this
![6 \frac{2}{3} * 3\frac{3}{10}](https://tex.z-dn.net/?f=6%20%5Cfrac%7B2%7D%7B3%7D%20%2A%203%5Cfrac%7B3%7D%7B10%7D%20)
To multiply fraction we have to transform into improper fractions
![\frac{20}{3}* \frac{33}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B20%7D%7B3%7D%2A%20%5Cfrac%7B33%7D%7B10%7D%20%20)
We can reduce 3 and 33 by cross reducing and 10 and 20
![\frac{2}{1} * \frac{11}{1} =2*11=22](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B1%7D%20%2A%20%5Cfrac%7B11%7D%7B1%7D%20%3D2%2A11%3D22)
- its the result.
Answer:
-10 but its 17
Step-by-step explanation: